來自SUM的MySQL MAX

這嚇我一跳！得到了以下數據：來自SUM的MySQL MAX

+----+-----+-------+------------+ 
| ID | REG | VALUE | DATE  | 
+----+-----+-------+------------+ 
| 1 | 1A | 100 | 2009-01-01 | 
| 1 | 1A | 100 | 2009-02-01 | 
| 1 | 1A | 100 | 2009-03-01 | 
| 2 | 1B | 100 | 2009-01-01 | 
| 2 | 1B | 100 | 2009-02-01 | 
| 2 | 1B | 100 | 2009-03-01 | 
| 2 | 1C | 100 | 2009-01-01 | 
| 2 | 1C | 100 | 2009-02-01 | 
| 2 | 1C | 200 | 2009-03-01 | 
+----+-----+-------+------------+

PS {編輯0001} ::還有一個額外的領域，也必須用於過濾數據，稱之爲{TYPE}，一個可以讓「單」或' MULTIPLE'作爲價值。

我想爲每個{ID}的SUM（每個不同的{REG}）得到最大值。很明顯，這是一個簡單的表示形式，表格最多可達64985928個寄存器，{DATE}是過濾數據。

這將是第一步得到的總和每個{REG}：

+----+------+ 
| ID | SUM | 
+----+------+ 
| 1 | 300 | 
| 2 | 300 | 
| 2 | 400 | 
+----+------+

這就是：

SELECT 
    SUM(value) 
FROM 
    table 
WHERE 
    (date BETWEEN '2009-01-01' AND '2009-03-01') 
GROUP BY 
    reg;

，然後從每個SUM，這就是我得到了MAX米stucked：

+----+------+ 
| ID | MAX | 
+----+------+ 
| 1 | 300 | 
| 2 | 400 | 
+----+------+

我已經試過：

SELECT 
    a.id, 
    MAX(b.sum) 
FROM 
    table a, 
    (SELECT 
    SUM(b.value) 
    FROM 
    table b 
    WHERE 
    (b.date BETWEEN '2009-01-01' AND '2009-03-01') AND (a.id = b.id) 
    GROUP BY 
    b.reg);

有什麼想法嗎？ PS：對不起。

PS {edit 0002}要複製原始查詢和數據，這樣可能會更好。

$查詢：

SELECT 
    clienteid AS "CLIENTE", 
    SUM(saldo) AS "SUMA" 
FROM 
    etl.creditos 
WHERE 
    (titularidad_tipo LIKE 'TITULAR') 
AND 
    (mes_datos BETWEEN '2008-11-01' AND '2009-10-01') 
GROUP BY 
    nuc 
ORDER BY 
    clienteid;

了：

+---------+-------------+ 
| CLIENTE | SUMA  | 
+---------+-------------+ 
| 64  | 1380690.74 | 
| 187  | 1828468.71 | 
| 187  | 2828102.80 | 
| 325  | 26037422.21 | 
| 389  | 875519.05 | 
| 495  | 20084.93 | 
| 495  | 109850.46 | 
+---------+-------------+

那麼，我正在尋找的是：

+---------+-------------+ 
| CLIENTE | MAX   | 
+---------+-------------+ 
| 64  | 1380690.74 | 
| 187  | 1828468.71 | 
| 325  | 26037422.21 | 
| 389  | 875519.05 | 
| 495  | 109850.46 | 
+---------+-------------+

但運行：

SELECT 
    clienteid AS "CLIENTE", 
    MAX(suma) 
FROM 
    (SELECT clienteid, SUM(saldo) AS "suma" FROM etl.creditos 
    WHERE (mes_datos BETWEEN '2009-08-01' AND '2009-10-01') AND (titularidad_tipo LIKE 'TITULAR') 
    GROUP BY clienteid, nuc) AS sums 
GROUP BY 
    clienteid 
ORDER BY 
    clienteid;

個

結果爲：

+---------+-------------+ 
| CLIENTE | SUMA  | 
+---------+-------------+ 
| 64  | 336879.21 | 
| 187  | 1232824.51 | 
| 325  | 3816173.62 | 
| 389  | 218423.83 | 
| 495  | 34105.99 | 
+---------+-------------+

來源

2013-08-26 Wolfchamane

你讀過「有」嗎？ – 7alhashmi

考慮提供一個sqlfiddle – Strawberry

SELECT ID, MAX(reg_sum) 
FROM 
(
    SELECT ID, SUM(value) AS reg_sum FROM table 
    WHERE (date BETWEEN '2009-01-01' AND '2009-03-01') 
    GROUP BY ID, reg 
) a GROUP by ID

來源

2013-08-26 09:47:53

如果我運行這個查詢，似乎每一個計算都是錯誤的。 – Wolfchamane

你可以講述什麼樣的計算錯誤，給出示例數據。 –

示例@ original post – Wolfchamane

您可以添加[通過SUM順序（值）DESC極限1]來獲得查詢結果的最大值。

SELECT SUM(value) as maxcount FROM table WHERE (date BETWEEN '2009 01-01' AND '2009-03-01') GROUP BY reg order by maxcount desc limit 1;

來源

2017-11-12 10:05:55

來自SUM的MySQL MAX

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