使用PHP解析和回顯JSON

Question

好吧，我已經在最後24小時內敲了敲頭，在測試和讀取SO之後無法弄清楚這一點。我有一個JSON文件，我需要解析，出於某種原因，我無法得到正確的代碼組合來回應除「數組」或「嘗試獲取非對象的屬性」或「爲foreach提供的無效參數以外的任何內容）」。這裏是我試圖迭代的完整JSON。我需要輸出每個「項目」的名稱，每個項目中的「數據集」以及每個「數據集」的「權限」。我自己構建這個JSON，所以我可以根據需要更改格式。

$data = json_decode($json, true); 

輸出JSON如下：

[ 
    [ 
     { 
     "projects":[ 
      { 
       "project":"test-project-1", 
       "datasets":[ 
        { 
        "dataset":"testing1", 
        "permissions":[ 
         { 
          "role":"READER", 
          "google_group":"testing1@test.com" 
         } 
        ] 
        }, 
        { 
        "dataset":"testing2", 
        "permissions":[ 
         { 
          "role":"OWNER", 
          "google_group":"testing2@test.com" 
         } 
        ] 
        }, 
        { 
        "dataset":"testing3", 
        "permissions":[ 
         { 
          "role":"READER", 
          "google_group":"testing3@test.com" 
         } 
        ] 
        }, 
        { 
        "dataset":"testing4", 
        "permissions":[ 
         { 
          "role":"WRITER", 
          "google_group":"testing4@test.com" 
         } 
        ] 
        } 
       ] 
      }, 
      { 
       "project":"test-project-2", 
       "datasets":[ 
        { 
        "dataset":"testing1", 
        "permissions":[ 
         { 
          "role":"READER", 
          "google_group":"testing1@test.com" 
         } 
        ] 
        }, 
        { 
        "dataset":"testing2", 
        "permissions":[ 
         { 
          "role":"READER", 
          "google_group":"testing2@test.com" 
         } 
        ] 
        }, 
        { 
        "dataset":"testing3", 
        "permissions":[ 
         { 
          "role":"READER", 
          "google_group":"testing3@test.com" 
         } 
        ] 
        }, 
        { 
        "dataset":"testing4", 
        "permissions":[ 
         { 
          "role":"READER", 
          "google_group":"testing4@test.com" 
         } 
        ] 
        } 
       ] 
      } 
     ] 
     } 
    ] 
] 

我已經試過了諸如：

foreach($data->projects as $output) 
{ 
    echo $output->project . "\n"; 
    foreach($output->datasets as $datasets) 
    { 
     echo $output->dataset . "\n"; 
    } 
} 

感謝您的幫助！

編輯：工作代碼解析JSON以上：

$projects = $json['projects']; 
foreach ($projects as $project) { 
    echo $project['project'] . "<br>"; 
    foreach ($json['projects'][0]['datasets'] as $datasets){ 
     echo $datasets['dataset'] . "<br>"; 
     foreach ($json['projects'][0]['datasets'][0]['permissions'] as $permissions){ 
      echo $permissions['role'] . "<br>"; 
      echo $permissions['google_group'] . "<br>"; 
     } 
    } 
} 

Answer 1

您的JSON包含兩個嵌套的數組，其中包含的對象，你想要的。所以首先你可以使用類似[0][0]的東西來獲得包含項目的關聯數組。

// ... 
$projects = $json['projects']; 
foreach ($projects as $project) { 
    echo "Project: " . $project['project'] . "\n"; 
    foreach ($project['datasets'] as $dataset) { 
     echo "Dataset: " . $dataset['dataset']; 
     foreach ($dataset['permissions'][0] as $key => $value) { 
      // ... 
     } 
    } 
}