PHP：從編碼解碼？

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我正在使用具有編碼鏈接選項的Flash播放器。我可以使用下面的代碼成功地對它們進行編碼，但是我找不到解碼的方法，並且它們不提供該選項。PHP：從編碼解碼？

鏈接與球員的工作，我的問題開始的時候，我需要對它們進行編輯。而不是我看到編碼版本的正常鏈接。

<?php 
    function uppod_enc_replace($str){ 
      $uppod_tmp_a=Array('G','d','R','0','M','Y','4','v','6','u','t','i','f','c','s','l','B','5','n','2','V','Z','J','m','L','='); 
      $uppod_tmp_b=Array('1','w','Q','o','9','U','a','N','x','D','X','7','z','H','y','3','e','g','T','W','b','8','k','I','p','r'); 
      $uppod_tmp=$str; 
      $uppod_tmp_from=$uppod_tmp_a; 
      $uppod_tmp_to=$uppod_tmp_b; 

      for($i=0;$i<sizeof($uppod_tmp_from);$i++){ 

       $uppod_tmp=uppod_enc_replace_ab($uppod_tmp_from[$i],$uppod_tmp_to[$i],$uppod_tmp); 
      } 
      return $uppod_tmp; 
    } 
    function uppod_enc_replace_ab($a,$b,$tmp){ 
      $tmp=preg_replace('/'.$a.'/','___',$tmp); 
      $tmp=preg_replace('/'.$b.'/',$a,$tmp); 
      $tmp=preg_replace('/___/',$b,$tmp); 
      return $tmp; 
    } 
    function uppod_encode($str,$lkey=''){ 
      $tmp=uppod_enc_replace(base64_encode($str)); 
      if($lkey!=''){ 
        $tmpn=rand(0,strlen($tmp)); 
        $tmp=substr($tmp,0,$tmpn).uppod_enc_replace(base64_encode($lkey)).substr($tmp,$tmpn); 
      } 
      return $tmp; 
    } 
?>

什麼我試過到目前爲止：

switching places 
        $uppod_tmp_from=$uppod_tmp_a; 
        $uppod_tmp_to=$uppod_tmp_b; 
changing base64_encode to base64_decode

測試：

stackoverflow.com 
encodes to: 
HlQhUWXNwIbs8I6NwsgjVWor 

changing base64_encode to base64_decode and switching places with $uppod_tmp_from=$uppod_tmp_a; $uppod_tmp_to=$uppod_tmp_b; 
decodes to: 
n!RB▒▒▒▒▒▒#Yj+[

來源

2012-10-20 Crazy_Bash

只是爲了澄清，這部分是無法解碼？服務器端還是客戶端？服務器端爲 – Leri

。當我編輯鏈接從acp我看到編碼版本。 –

後切換字母后面

BASE64_DECODE（）通過稍微修改uppod_enc_replace功能：

function uppod_enc_replace($str, $direction = 'encode'){ 
    $uppod_tmp_a=Array('G','d','R','0','M','Y','4','v','6','u','t','i','f','c','s','l','B','5','n','2','V','Z','J','m','L','='); 
    $uppod_tmp_b=Array('1','w','Q','o','9','U','a','N','x','D','X','7','z','H','y','3','e','g','T','W','b','8','k','I','p','r'); 
    $uppod_tmp=$str; 
    if($direction == 'encode'){ 
     $uppod_tmp_from = $uppod_tmp_a; 
     $uppod_tmp_to = $uppod_tmp_b; 
    }else{ 
     $uppod_tmp_to = $uppod_tmp_a; 
     $uppod_tmp_from = $uppod_tmp_b; 
    } 

    for($i=0;$i<sizeof($uppod_tmp_from);$i++){ 
     $uppod_tmp=uppod_enc_replace_ab($uppod_tmp_from[$i],$uppod_tmp_to[$i],$uppod_tmp); 
    } 
    return $uppod_tmp; 
}

解碼E類功能看起來就像這樣：

function uppod_decode($str, $lkey = ''){ 
    if($lkey!=''){ 
     $eKey = uppod_enc_replace(base64_decode($lkey)); 
     $str = str_replace($eKey, '', $str); 
    } 
    return base64_decode(uppod_enc_replace($str, 'decode')); 
}

測試用例：

$url = 'http://www.google.com/'; 

$encoded = uppod_encode($url); 
$decoded = uppod_decode($encoded); 

var_dump($decoded); 

$key = base64_encode('p45sw0rd'); 

$encoded2 = uppod_encode($url, $key); 
$decoded2 = uppod_decode($encoded2, $key); 

var_dump($decoded2); 

// outputs: 
// string(22) "http://www.google.com/" 
// string(22) "http://www.google.com/"

來源

2012-10-20 11:24:04

工作！非常感謝！ –

編碼腳本是這樣做的：

BASE64_ENCODE（）
SWITC興一些字母

所以要對其進行解碼，您需要：

來源

2012-10-20 11:06:01 Savageman

這就是我所做的，但我得到了胡言亂語 –

PHP：從編碼解碼？

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