我可以在CASE語句中使用變量條件嗎？

Question

圖片此表交互的業務與人們：

+-----------+---------------------+-----------------+ 
| user_name | action_timestamp | action   | 
+-----------+---------------------+-----------------+ 
| john  | 2017-01-01 10:00:00 | phone_call  | 
+-----------+---------------------+-----------------+ 
| john  | 2017-01-02 12:00:00 | became_customer | 
+-----------+---------------------+-----------------+ 
| john  | 2017-01-03 14:00:00 | phone_call  | 
+-----------+---------------------+-----------------+ 
| jane  | 2016-08-06 10:00:00 | phone_call  | 
+-----------+---------------------+-----------------+ 
| jane  | 2016-08-06 11:00:00 | phone_call  | 
+-----------+---------------------+-----------------+ 
| jane  | 2016-08-06 12:00:00 | became_customer | 
+-----------+---------------------+-----------------+ 
| tony  | 2016-12-01 15:00:00 | phone_call  | 
+-----------+---------------------+-----------------+ 

我想要得到的東西是這樣的：

+-----------+---------------+-------------+---------------------+------------------------------+-----------------------------+ 
| user_name | total_actions | is_customer | became_customer  | interactions_before_customer | interactions_after_customer | 
+-----------+---------------+-------------+---------------------+------------------------------+-----------------------------+ 
| john  | 3    | TRUE  | 2017-01-02 12:00:00 | 1       | 1       | 
+-----------+---------------+-------------+---------------------+------------------------------+-----------------------------+ 
| jane  | 3    | TRUE  | 2016-08-06 12:00:00 | 2       | 0       | 
+-----------+---------------+-------------+---------------------+------------------------------+-----------------------------+ 
| tony  | 1    | FALSE  | NULL    | 1       | 0       | 
+-----------+---------------+-------------+---------------------+------------------------------+-----------------------------+ 

第4列是微不足道的一些分組和案例，但我不知道如何做第5和第6列（客戶之前的交互以及客戶之後的交互），因爲案例是根據前一列的結果進行判斷的，需要在行之間進行變化。

這是比它顯得更簡單嗎？如果有人關心，我不在呼叫中心工作，它只是一個更簡單的模擬我想要做的;）

Answer 1

這會給你一個想法。我已經在ORACLE測試這一點，它工作正常，

WITH CUS_DET AS (
    SELECT * 
    FROM INTERACTIONS 
    WHERE ACTION = 'became_customer' 
) 
SELECT INTERACTIONS.USER_NAME 
    , SUM(CASE 
    WHEN (CUS_DET.ACTION_TIMESTAMP IS NULL 
      OR INTERACTIONS.ACTION_TIMESTAMP < CUS_DET.ACTION_TIMESTAMP) 
    THEN 1 
    ELSE 0 
    END) BEF 
    , SUM(CASE 
    WHEN INTERACTIONS.ACTION_TIMESTAMP > CUS_DET.ACTION_TIMESTAMP 
    THEN 1 
    ELSE 0 
    END) AFT 
FROM INTERACTIONS 
    LEFT OUTER JOIN CUS_DET 
    ON INTERACTIONS.USER_NAME = CUS_DET.USER_NAME 
GROUP BY INTERACTIONS.USER_NAME; 

Answer 2

使用條件聚合如果一個用戶只能成爲客戶的一次：

select 
    t.user_name 
    , case when c.action_timestamp is not null then 'Yes' else 'No' end as Is_Customer 
    , c.action_timestamp as became_customer 
    , count(case when t.action_timestamp < coalesce(c.action_timestamp,'2525-01-01') then 1 end) as interactions_before_customer 
    , count(case when t.action_timestamp > c.action_timestamp then 1 end) as interactions_after_customer 
from t 
    left join t as c 
    on t.user_name = c.user_name 
     and c.action = 'became_customer' 
group by t.user_name, c.action_timestamp 

rextester演示：http://rextester.com/LOUGN53032

+-----------+-------------+---------------------+------------------------------+-----------------------------+ 
| user_name | Is_Customer | became_customer | interactions_before_customer | interactions_after_customer | 
+-----------+-------------+---------------------+------------------------------+-----------------------------+ 
| tony  | No   | NULL    |       1 |       0 | 
| jane  | Yes   | 2016-08-06 12:00:00 |       2 |       0 | 
| john  | Yes   | 2017-01-02 12:00:00 |       1 |       1 | 
+-----------+-------------+---------------------+------------------------------+-----------------------------+