的Java源碼 - 顯示選擇

Question

這些都是我的表：
http://sqlfiddle.com/#!5/acdb1

我想在Java中類似raport顯示：

Connection c = null; 
    Statement stmt = null; 
    try { 
     Class.forName("org.sqlite.JDBC"); 
     c = DriverManager.getConnection("jdbc:sqlite:project.db"); 
     c.setAutoCommit(false); 
     System.out.println("Opened database successfully"); 

     stmt = c.createStatement(); 
     ResultSet rs = stmt.executeQuery("SELECT stormtrooper.id, squad.id, platoon.id, company.id, battalion.id FROM stormtrooper\n" + 
"INNER JOIN squad ON squad.id=stormtrooper.squad\n" + 
"INNER JOIN platoon ON platoon.id=squad.platoon\n" + 
"INNER JOIN company ON company.id=platoon.company\n" + 
"INNER JOIN battalion ON battalion.id=company.battalion;"); 
     String log = ""; 
     while (rs.next()) { 
     log+=rs.getInt("id") + " | "; 
     log+=rs.getInt("id") + " | "; 
     log+=rs.getInt("id") + " | "; 
     log+=rs.getInt("id") + " | "; 
     log+=rs.getInt("id") + "\n"; 
     } 
     jTextArea1.setText(log); 
     rs.close(); 
     stmt.close(); 
     c.close(); 
    } catch (Exception e) { 
     jTextArea1.setText(e.getClass().getName() + ": " + e.getMessage()); 
    } 

SELECT語句是正確的 - 我查這個。但是，當我試圖在Java中執行此，我得到一個錯誤：

ambiguous column: 'id' 

應該如何樣子？

Answer 1

你有很多id列在你的SELECT聲明

你有一些像這樣的改變的列名：

SELECT stormtrooper.id AS stormtrooper_id, squad.id AS squad_id, platoon.id AS platoon_id, company.id AS company_id, battalion.id AS battalion_id FROM ...