Hibernate的過濾器不工作

Question

我有OneToOne映射兩個實體定義如下：

類別

@Entity 
@Table(name = "category") 
@FilterDef(name = "currentLang", parameters = { 
    @ParamDef(name = "lang", type = "string") 
}) 
public class Category implements Serializable { 

    @Id 
    @NotNull 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name = "id") 
    private int id; 

    @Column(name = "dt") 
    private String dt; 

    @Column(name = "enable", length = 5) 
    private String enable; 

    @OneToOne() 
    @Filter(name = "currentLang", condition = ":lang = lang") 
    @JoinColumn(name = "context_id", nullable = false, updatable = false, referencedColumnName = "link") 
    private Context context; 

    public int getId() { 
     return id;//test 
    } 

    public void setId(int id) { 
     this.id = id; 
    } 

    public String getDt() { 
     return dt; 
    } 

    public void setDt(String dt) { 
     this.dt = dt; 
    } 

    public String getEnable() { 
     return enable; 
    } 

    public void setEnable(String enable) { 
     this.enable = enable; 
    } 

    public Context getContext() { 
     return context; 
    } 

    public void setContext(Context context) { 
     this.context = context; 
    } 

    public Category() { 
    } 

    public Category(String dt, String enable) { 
     this.dt = dt; 
     this.enable = enable; 
    } 
} 

語境

@Entity 
@Table(name = "context") 
@Component 
@Scope("session") 
public class Context implements Serializable { 

    @Id 
    @NotNull 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    @Column(name = "id") 
    private int id; 

    @Column(name = "text") 
    private String text; 

    @Column(name = "lang") 
    private String lang; 

    @Column(name = "link") 
    private Integer link; 

    public int getId() { 
     return id; 
    } 

    public void setId(int id) { 
     this.id = id; 
    } 

    public String getText() { 
     return text; 
    } 

    public void setText(String text) { 
     this.text = text; 
    } 

    public String getLang() { 
     return lang; 
    } 

    public void setLang(String lang) { 
     this.lang = lang; 
    } 

    public Context(String text, String lang) { 
     this.text = text; 
     this.lang = lang; 
    } 

    public Context() { 
    } 

    public Integer getLink() { 
     return link; 
    } 

    public void setLink(Integer link) { 
     this.link = link; 
    } 
} 

下面的代碼片段檢索模型類別。

List<com.blog.blog.entity.Category> categories = categoryService.getAll(); 
    com.blog.blog.entity.Category category = categories.get(0); 

    org.apache.log4j.Logger.getRootLogger().addAppender(new ConsoleAppender(new PatternLayout(PatternLayout.TTCC_CONVERSION_PATTERN))); 
    Logger logger = org.slf4j.LoggerFactory.getLogger(this.getClass()); 
    logger.info(category.getEnable()); 
    logger.info(category.getContext().getText()); 

但過濾器不工作，結果是錯誤的，並且在日誌中記錄了錯誤的查詢。

Info: Hibernate: select category0_.id as id1_0_, category0_.context_id as context_4_0_, category0_.dt as dt2_0_, category0_.enable as enable3_0_ from category category0_ 
Info: Hibernate: select context0_.id as id1_1_0_, context0_.lang as lang2_1_0_, context0_.link as link3_1_0_, context0_.text as text4_1_0_ from context context0_ where context0_.link=? 

Answer 1

您需要啓用過濾器，如果需要

Session session = sessionFactory.getCurrentSession(); 
Filter filter = session.enableFilter("currentLang"); 
filter.setParameter("lang", getLang());