這裏是我的值編碼:如何在java中刪除列表中的元素數組?
package Controls;
// Other code
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
response.getWriter().write("<h5 class='searchResultFramePara'>Assigned roles</h5>");
String[] Removelist = request.getParameterValues("deleterolelist");
//String[] Removelist=removelist.split(",");
//System.out.println(Removelist);
String username = request.getParameter("name");
//System.out.println(username);
List<String> Removelist1 = new ArrayList<String>();
Connection Con = null;
Statement st = null;
ResultSet rs;
int rs1;
try {
Con = LoginSrv1.getConnection();
st = Con.createStatement();
String roles_query = "SELECT ROLE_NAME FROM demo.ZMM_USER_GROUP WHERE USER_NAME = '" + username + "';";
rs = st.executeQuery(roles_query);
while (rs.next()) {
String assigned_role = rs.getString("ROLE_NAME");
String[] assigned_array = assigned_role.split(",");
if (assigned_array != null) {
for (int i = 0; i < assigned_array.length; i++) {
Removelist1.add(assigned_array[i]);
}
}
}
for (int j = 0; j < Removelist.length; j++) {
if (Removelist1.contains(Removelist[j])) {
Removelist1.remove(Removelist[j]);
}
}
System.out.println(Removelist1);
StringBuilder b = new StringBuilder();
for (String text1 : Removelist1) {
b.append(text1).append(",");
}
String Roletext = b.toString().replaceAll(",$", "");
System.out.println(Roletext);
String update_query = "UPDATE DEMO.ZMM_USER_GROUP SET ROLE_NAME='" + Roletext + "' WHERE USER_NAME = '" + username + "';";
rs1 = st.executeUpdate(update_query);
String assignedrole_query = "SELECT ROLE_NAME FROM demo.ZMM_USER_GROUP WHERE USER_NAME = '" + username + "';";
rs = st.executeQuery(assignedrole_query);
while (rs.next()) {
String rolename = rs.getString("ROLE_NAME");
String[] sarr = rolename.split(",");
for (int i = 0; i < sarr.length; i++) {
//System.out.println("array"+i+sarr[i]);
response.getWriter().write("<a href='javascript:void(0);' id=" + sarr[i] + " class='availalbe' onclick='removelist(\"" + sarr[i] + "\");'>" + sarr[i] + "</a><br>");
}
}
} catch (Exception e) {
System.out.println(e);
}
}
在這裏,我得到Removelist陣列和角色名來自阿賈克斯的請求。現在我刪除Removelist1列表中的removelist。例如我發送具有一個字符串值「發起者」的Removelist,然後它將被刪除。但是,例如它包含「發起者」,「生產管理者」(即,數組包含多個值),那麼它不會刪除它。
有很多的代碼在這裏,如果你發佈你會得到更多的幫助短的,獨立的,正確的(可編譯),實例 - http://sscce.org/ – SimonC
如果我正確地得到你的意思,你的意思是你有一些需要在其他一些(Removelist)集合中刪除的數據的集合。如果是這種情況,你可以使用ArrayList的removeAll()。 – guptakvgaurav
「不會刪除」是什麼意思? remove()拋出異常,或返回false,什麼?對於(int j = 0; j