傳遞查詢字符串來形成選擇選項

Question

嗨，大家好我有這樣的代碼，檢查linkback：

$reciprocal_linkback = reciprocal_linkback("$contenturl","http://www.mydomain.com",1); 

if ("$reciprocal_linkback"=="0") { 

$contenturl是會反對我的網站進行檢查URL（http://www.mydomain.com）

的問題是，我需要檢查網址和主頁面。 我用這個代碼：

$parse = parse_url($contenturl); 

而結果在最後會是這樣：

$parse = parse_url($contenturl); 
$reciprocal_linkback = reciprocal_linkback("$contenturl, $parse","http://www.mydomain.com",1); 

    if ("$reciprocal_linkback"=="0") { 

林不知道如何使用多個變量，例如$contenturl, $parse，所以我可以覈對我的域名這兩個鏈接。

我將不勝感激任何幫助。

Siconerely。

編輯：繼承人的功能

function reciprocal_linkback($check_url, $link, $strict = "0") { 

    global $global; 
    global $field; 

    $field['hostname'] = ""; 
    $field['hostname_port'] = "80"; 
    $field['result'] = "0"; 

    preg_match("/^(http:\/\/)?([^\/]+)/i",$check_url, $field['hostname']); 

    $field['hostname_short'] = $field['hostname'][2]; 
    $field['hostname_end'] = str_replace($field['hostname'][0], "", $check_url); # We don't want http://, we want the domain 

    $field['url_get'] = fsockopen($field['hostname_short'], $field['hostname_port']); # Connect to domain 

    if ($field['url_get']) { # We're connected... 

     if(trim($field['hostname_end'])=="") { # No filename, add a slash to end URL 

      $field['hostname_page'] = "/"; 

     } else { 

      $field['hostname_page'] = $field['hostname_end']; # Filename 

     } 

     fputs($field['url_get'], "GET ".$field['hostname_page']." HTTP/1.0\r\nHost: ".$field['hostname_short']."\r\n\r\n"); # Request page from domain 

     $field['url_content'] = ""; 

     while(!feof($field['url_get'])) { # Get data by line and store 

      $field['url_content'] .= fgets($field['url_get'], 10240); 

     } 

     if (eregi($link, $field['url_content'])) { # Can we find the URL in the page? 

      if ("$strict"=="1") { # Check for nofollow 

       $field['result'] = "1"; # Success, we have a link, now check for nofollow 

       $field['link_position'] = strpos($field['url_content'], $link); # Find position of URL being checked 

       $field['link_html_end'] = substr($field['url_content'],($field['link_position'] + strlen($link)),200); # Get HTML after URL 
       $field['link_html_start'] = substr($field['url_content'],($field['link_position'] - strlen($link) - 100),200); # Get HTML before URL 

       $field['link_html_end_explode'] = explode(">",$field['link_html_end']); 
       $field['link_html_start_explode'] = explode("<",$field['link_html_start']); 

       $link_html_start_count = count($field['link_html_start_explode']) - 1; 
       $field['link_html_start_explode'] = explode("=",$field['link_html_start_explode'][$link_html_start_count]); 

       $field['link_html_tag'] = $field['link_html_end_explode'][0].$field['link_html_start_explode'][0]; # Get link HTML, without URL and surrounding HTML 

       if (eregi("nofollow", $field['link_html_tag'])) { # Can we find a nofollow tag in link HTML? 

        $field['result'] = "0"; # Nofollow tag found 

       } 

      } else { 

       $field['result'] = "1"; # Success, we have a link, but nofollow not checked 

      } 
     } 

     fclose($field['url_get']); 

    } else { 

     $field['result'] = "2"; # Cannot read page 

    } 

    return $field['result']; 

} 

以及完整的代碼我上面提及：

// Check to see if have backlink and nofollow atribute 

$reciprocal_linkback = reciprocal_linkback("$contenturl","http://www.dumpvid.com",1); 

if ("$reciprocal_linkback"=="0") { 

$_SESSION['submitstatus'] = "<div class=error><b>Error:</b> Backlink was not found, or nofollow detected.</div> "; 
header('Location: '.$frompage.''); 
exit; 

} 

我需要檢查它的網址本身來自同一URL的域。

那就是爲什麼我使用$ parse = parse_url（$ contenturl）;僅在domain.tld中轉換url，但dint起作用。

Answer 1

你可以那樣做：

$contenturl = "http://domain.com/video_content.html"; 
$parse = parse_url($contenturl); 
$base_url = $parse["host"]; // domain.com 

，並調用它兩次：

$linkback1 = reciprocal_linkback($contenturl, "http://www.mydomain.com", 1); 
$linkback2 = reciprocal_linkback($base_url, "http://www.mydomain.com", 1);