如何找到當前節點（n）和前一個節點（n-1）的差異

請您幫助並建議如何將節點插入到我的XML文件中，從而使此節點具有以下內部值：差異當前節點和前一個節點之間（只有一個先前的數據）。如何找到當前節點（n）和前一個節點（n-1）的差異

我輸入XML是：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?> 
    <Root> 
     <Test> 
     <TestPhase>1</TestPhase> 
     <TestFlow>1</TestFlow> 
     <TestParameter>1</TestParameter> 
     <OriIndex>0</OriIndex> 
     </Test> 
     <Test> 
     <TestPhase>1</TestPhase> 
     <TestFlow>1</TestFlow> 
     <TestParameter>2</TestParameter> 
     <OriIndex>1</OriIndex> 
     </Test> 
     <Test> 
     <TestPhase>1</TestPhase> 
     <TestFlow>3</TestFlow> 
     <TestParameter>1</TestParameter> 
     <OriIndex>2</OriIndex> 
     </Test> 
     <Test> 
     <TestPhase>1</TestPhase> 
     <TestFlow>2</TestFlow> 
     <TestParameter>2</TestParameter> 
     <OriIndex>3</OriIndex> 
     </Test> 
     <Test> 
     <TestPhase>2</TestPhase> 
     <TestFlow>1</TestFlow> 
     <TestParameter>1</TestParameter> 
     <OriIndex>4</OriIndex> 
     </Test> 
. 
. 
. 
. 
.

我的XSLT是：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> 

<xsl:output method="xml" encoding = "UTF-8" indent="yes" omit-xml-declaration="no" standalone="yes" /> 


    <xsl:template match="Root"> 
    <xsl:copy> 
    <xsl:apply-templates select="Test"> 
     <xsl:sort select="TestPhase" data-type="number" order="ascending"/> 
     <xsl:sort select="TestFlow" data-type="number" order="ascending"/> 
     <xsl:sort select="TestParameter" data-type="number" order="ascending"/> 
    </xsl:apply-templates> 
    </xsl:copy> 
    </xsl:template> 


    <xsl:template match="@* | node()"> 
    <xsl:copy> 
      <xsl:apply-templates select="@* | node()"/> 
    </xsl:copy> 
    </xsl:template> 


    <xsl:template match="Test"> 
    <xsl:copy> 
     <xsl:apply-templates select="@* | *"/> 
     <SortedIndex><xsl:value-of select="position() - 1"/></SortedIndex> 
     <DiffSortedIndex><xsl:value-of select="position() - 1 - OriIndex" /></DiffSortedIndex> 
     <DiffOriIndex><xsl:value-of select="OriIndex - preceding-sibling::Test[position()-1]/OriIndex" /></DiffOriIndex> 
    </xsl:copy> 
    </xsl:template> 


</xsl:stylesheet>

我的輸出XML是：

<?xml version="1.0" encoding="utf-8" standalone="yes"?> 
<Root> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>1</TestFlow> 
    <TestParameter>1</TestParameter> 
    <OriIndex>0</OriIndex> 
    <SortedIndex>0</SortedIndex> 
    <DiffSortedIndex>0</DiffSortedIndex> 
    <DiffOriIndex>NaN</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>1</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>1</OriIndex> 
    <SortedIndex>1</SortedIndex> 
    <DiffSortedIndex>0</DiffSortedIndex> 
    <DiffOriIndex>NaN</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>2</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>3</OriIndex> 
    <SortedIndex>2</SortedIndex> 
    <DiffSortedIndex>-1</DiffSortedIndex> 
    <DiffOriIndex>NaN</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>2</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>12</OriIndex> 
    <SortedIndex>3</SortedIndex> 
    <DiffSortedIndex>-9</DiffSortedIndex> 
    <DiffOriIndex>NaN</DiffOriIndex> 
    </Test> 
. 
. 
. 
. 
.

我的預期成果是：

<?xml version="1.0" encoding="utf-8" standalone="yes"?> 
<Root> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>1</TestFlow> 
    <TestParameter>1</TestParameter> 
    <OriIndex>0</OriIndex> 
    <SortedIndex>0</SortedIndex> 
    <DiffSortedIndex>0</DiffSortedIndex> 
    <DiffOriIndex>NaN</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>1</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>1</OriIndex> 
    <SortedIndex>1</SortedIndex> 
    <DiffSortedIndex>0</DiffSortedIndex> 
    <DiffOriIndex>1</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>2</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>3</OriIndex> 
    <SortedIndex>2</SortedIndex> 
    <DiffSortedIndex>-1</DiffSortedIndex> 
    <DiffOriIndex>2</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>2</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>12</OriIndex> 
    <SortedIndex>3</SortedIndex> 
    <DiffSortedIndex>-9</DiffSortedIndex> 
    <DiffOriIndex>9</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>1</TestPhase> 
    <TestFlow>3</TestFlow> 
    <TestParameter>1</TestParameter> 
    <OriIndex>2</OriIndex> 
    <SortedIndex>4</SortedIndex> 
    <DiffSortedIndex>2</DiffSortedIndex> 
    <DiffOriIndex>-10</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>2</TestPhase> 
    <TestFlow>1</TestFlow> 
    <TestParameter>1</TestParameter> 
    <OriIndex>4</OriIndex> 
    <SortedIndex>5</SortedIndex> 
    <DiffSortedIndex>1</DiffSortedIndex> 
    <DiffOriIndex>2</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>2</TestPhase> 
    <TestFlow>1</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>5</OriIndex> 
    <SortedIndex>6</SortedIndex> 
    <DiffSortedIndex>1</DiffSortedIndex> 
    <DiffOriIndex>1</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>2</TestPhase> 
    <TestFlow>2</TestFlow> 
    <TestParameter>1</TestParameter> 
    <OriIndex>6</OriIndex> 
    <SortedIndex>7</SortedIndex> 
    <DiffSortedIndex>1</DiffSortedIndex> 
    <DiffOriIndex>1</DiffOriIndex> 
    </Test> 
    <Test> 
    <TestPhase>2</TestPhase> 
    <TestFlow>2</TestFlow> 
    <TestParameter>2</TestParameter> 
    <OriIndex>7</OriIndex> 
    <SortedIndex>8</SortedIndex> 
    <DiffSortedIndex>1</DiffSortedIndex> 
    <DiffOriIndex>1</DiffOriIndex> 
    </Test> 
. 
. 
. 
. 
.

我無法得到正確的1部分。預期的內部值= OriIndex（當前位置） - OriIndex（前一位置）或OriIndex（位置n） - OriIndex（位置n-1）。

請幫我解決這個問題。您的努力非常感謝。

非常感謝。

乾杯！

來源

2017-09-27 newbuntu

我用xml linq。您預期輸出不會與您的輸入xml使用相同的xml，因此我的結果與您的結果不匹配。我認爲我的代碼是正確的。

using System; 
using System.Collections.Generic; 
using System.Linq; 
using System.Text; 
using System.Xml; 
using System.Xml.Linq; 

namespace ConsoleApplication1 
{ 
    class Program 
    { 
     const string FILENAME = @"c:\temp\test.xml"; 
     static void Main(string[] args) 
     { 
      XDocument doc = XDocument.Load(FILENAME); 

      List<XElement> tests = doc.Descendants("Test").OrderBy(x => (int)x.Element("OriIndex")).ToList(); 

      int previousOriIndex = 0; 
      for (int i = 0; i < tests.Count; i++) 
      { 
       XElement test = tests[i]; 
       int currentOriIndex = (int)test.Element("OriIndex"); 
       test.Add(new XElement("SortedIndex", i)); 
       test.Add(new XElement("DiffSortedIndex", i - currentOriIndex)); 

       if (i == 0) 
       { 
        test.Add(new XElement("DiffOriIndex", "NaN")); 
       } 
       else 
       { 
        test.Add(new XElement("DiffOriIndex", currentOriIndex - previousOriIndex)); 
       } 
       previousOriIndex = currentOriIndex; 

      } 
     } 
    } 

}

來源

2017-09-27 05:59:45 jdweng

謝謝jdweng。我無法使用Linq，因爲需求是.NET2.0。這就是我選擇使用XSLT和Xpath的原因。非常感謝你。 – newbuntu

謝謝女士們，先生們。該解決方案可見[鏈接] https://stackoverflow.com/questions/46430620/how-to-get-the-difference-between-previous-and-current-node-inner-text-value/46431919?noredirect= 1＃comment79864370_46431919。你們都很有幫助。謝謝，乾杯！ – newbuntu

如何找到當前節點（n）和前一個節點（n-1）的差異

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