在每一行添加一個接受和拒絕按鈕

我試圖在每一行上添加一個按鈕，我已經做了。當我點擊更新數據庫上的某個字段時，它不起作用。當按鈕被點擊時，它被重定向到approve.php文件。在每一行添加一個接受和拒絕按鈕

<?php 
$con=mysqli_connect("localhost","root","","rabco");// Check connection 
if (mysqli_connect_errno()) 
{ 
echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 
$result = mysqli_query($con,"SELECT * FROM service_request"); 


        echo "<table border='1'> 
        <tr> 
        <th>Service ID</th> 
        <th>Service Type</th> 
        <th>Schuduled Date</th> 
        <th>Scheduled Time</th> 
        <th>Client Reference 
        <th>Client ID</th> 
        <th>Admin ID</th> 
        <th>Special Instructions</th> 
        <th>Status</th> 
        <th>Approve</th> 
        <th>Decline</th> 
        </tr>"; 

        while($row = mysqli_fetch_array($result)) 
        { 
        echo "<tr>"; 
        echo "<td>" . $row['Service_ID'] . "</td>"; 
        echo "<td>" . $row['Service_type'] . "</td>"; 
        echo "<td>" . $row['Sched_date'] . "</td>"; 
        echo "<td>" . $row['Sched_time'] . "</td>"; 
        echo "<td>" . $row['Client_reference'] . "</td>"; 
        echo "<td>" . $row['Client_IDN'] . "</td>"; 
        echo "<td>" . $row['Admin_IDN'] . "</td>"; 
        echo "<td>" . $row['Special_instructions'] . "</td>"; 
        echo "<td>" . $row['Request_status'] . "</td>"; 
        echo "<td><form action='approve.php' method='POST'>  <input type='hidden' name='accept' value='".$row["Service_ID"]."'/><input type='submit' name='submit' value='Approve'/></form></td>"; 
        echo "<td><form action='decline.php' method='POST'><input type='hidden' name='decline' value='".$row["Service_ID"]."'/><input type='submit' name='submit' value='Decline'/></form></td>"; 
        } 
        echo "</tr>"; 
        echo "</table>"; 

        mysqli_close($con); 
       ?> 



approve.php 
<?php 
$link = mysqli_connect("localhost", "root", "", "rabco"); 
if(isset($_GET["Service_ID"])) 
{ 
$row_sr=$_GET["Service_ID"]; 
$sql="UPDATE service_request SET Request_status = 'Approved', Admin_IDN =  '$_SESSION[Admin_ID]', Paid = 'Php 17,500', Balance = 'Php 32,500', Total_price  = 'Php 50,000' WHERE Service_ID = '$row_sr'"; 
$result=mysqli_query($sql); 
mysqli_query($link,$result); 
if($result==1) 
{ 
header('location: adminpage-sr.php'); 
} 
} 
?>

來源

2015-11-08 Samuel John Paul Santos

您正在使用您的主文件，但在方法POST批准PHP使用$ _GET？

根據您的approve.php文件，你可以改變你的按鈕：

"<td><a href='approve.php?Service_ID='.$row["Service_ID"].">Approve</a></td>"

來源

2015-11-08 09:17:41

仍然沒有運氣爵士。：（（（（ –

你是否改變按鈕或更改approve.php？如果你不想改變按鈕，只需將您的approve.php中的所有$ _GET [「Service_ID」]更改爲$ _POST [「Service_ID」]，我認爲這將工作 –

我改變了按鈕根據您的代碼 –

在每一行添加一個接受和拒絕按鈕

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