PHP樂趣codeing

Question

嘿，我做一個簡單的PHP表環......它會是這樣......

1 2 3 4 5 
6 7 8 9 10 
11 12 13 14 15 

但問題是，使用一個循環我無法打印該值在列內......那麼解決方案是什麼？請

我的代碼：

echo "<table border=1>\n"; 
for($row=1;$row<=3;$row++) 
{ 
    echo "<tr>"; 
    for($col=1;$col<=5;$col++) 
    { 
     echo "<td>"; 
     echo "MY PROBLEM HERE...I cant print column numbers \n"; 
     echo "</td>"; 
    } 
    echo "</tr>"; 
} 
echo "</table> \n"; 

Answer 1

保存多循環：

$rows = 3; 
$cols = 5; 

$table = '<table border="1">'; 

for($i=1;$i<=$rows;$i++){ 
    $table .= '<tr><td>'.implode('</td><td>', range($cols*$i-$cols+1,$cols*$i)).'</td></tr>'; 
} 

$table .= '</table>'; 
echo $table; 

Answer 2

echo "<table border=1>\n"; 
for($row=1;$row<=3;$row++) 
{ 
    echo "<tr>"; 
    for($col=1;$col<=5;$col++) 
    { 
     echo "<td>"; 
     //echo "MY PROBLEM HERE...I cant print column numbers \n"; 
     echo $col + ($row - 1) * 5; 
     echo "</td>"; 
    } 
    echo "</tr>"; 
} 
echo "</table> \n"; 

Answer 3

這不是$col + $row * 5它必須是$row - 1

<?php 
echo "<table border=1>\n"; 
for($row=1;$row<=3;$row++) 
{ 
    echo "<tr>"; 
    for($col=1;$col<=5;$col++) 
    { 
     echo "<td>"; 
     echo $col + ($row-1) * 5; 
     echo "</td>"; 
    } 
    echo "</tr>"; 
} 
echo "</table> \n"; 

?>