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def interval(a,b,n):
dx = float(b-a)/(n+1)
cnt = 1
points = [a]
xj = a
while cnt <= n+1:
xj += dx
points.append(xj)
cnt+=1
return points
def interval(a,b,n):
dx = float(b-a)/(n+1)
cnt = 1
points = [a]
xj = a
while cnt <= n+1:
xj += dx
points.append(xj)
cnt+=1
return points
更換你的函數如下給出: -
def interval(a,b,n):
dx = float(b-a)/(n+1)
points = [a]
xj = a
points.extend([xj + (i * dx) for i in xrange(1, n+2)])
return points
爲什麼你需要它作爲一個列表理解? – wwii
,因爲列表理解比循環操作簡單和短。 – user59220
是什麼問題?請嘗試。 – wwii