Spring MVC：使用ManyToOne/OneToMany關係存儲數據

我在我的項目中使用Spring-mvc & Spring-data-jpa。我有這兩個實體Spring MVC：使用ManyToOne/OneToMany關係存儲數據

Location.java：

@Entity 
@Table(name = "location") 
@JsonIgnoreProperties(ignoreUnknown = true) 
public class Location { 
    @Id 
    @GeneratedValue 
    private int id; 

    // other attributes... 

    @ManyToOne(optional=true) 
    @JoinColumn(name ="user") 
    @JsonBackReference 
    private User user; 

    @ManyToOne(optional=true) 
    @JoinColumn(name ="client") 
    @JsonBackReference 
    private Client client; 

    public int getId() { 
     return id; 
    } 

    public void setId(int id) { 
     this.id = id; 
    } 

    // getters & setters 

}

User.java：

@Entity 
@Table(name = "users") 
@JsonIgnoreProperties(ignoreUnknown = true) 
public class User { 

    @Id 
    @GeneratedValue 
    private int uid; 

    // other attributes... 

    @OneToMany(mappedBy="user") 
    @JsonManagedReference 
    private List<Location> locations; 

    // getters & setters... 

    @JsonIgnore 
    public List<Location> getLocations() { 
     return locations; 
    } 

    public void setLocations(List<Location> locations) { 
     this.locations = locations; 
    } 

}

什麼我想要做的是增加一個新的位置，並將其鏈接到現有用戶。對於這兩個實體都有一個存儲庫和一個服務。 LocationRepository.java：

public interface LocationRepository extends CrudRepository<Location, Integer> { 

    List<Location> findAll(); 

    //.... 

}

LocationService.java

@Service 
public class LocationService { 

    @Autowired 
    private LocationRepository locationRepository; 


    public List<Location> findAll() { 
     return locationRepository.findAll(); 
    } 

    public void save(Location location) { 
     locationRepository.save(location); 
    } 

    @Secured("ROLE_ADMIN") 
    public void delete(int locationId) { 
     locationRepository.delete(locationId); 
    } 
}

ApiController.java

@Controller 
@RequestMapping(value = "/rest/api") 
public class ApiController { 

    @Autowired 
    UserService userService; 
    @Autowired 
    LocationService locationService; 

    // Storing a new location 

    @RequestMapping(value = "/locations/checkin", method = RequestMethod.POST, produces = "application/json") 
    public ResponseEntity<?> checkin(@ModelAttribute("location") Location location) { 
     locationService.save(location); 
     List<Location> locationslist = locationService.findAll(); 
     return new ResponseEntity<List<Location>>(locationslist, HttpStatus.OK); 
    } 

}

一切似乎罰款至今。我爲Android客戶端使用Restfull服務，我所要做的就是重新構建一個新的Location對象，並通過POST請求將其發送給正確的URI。

這是對象的結構：

{ 
    "id":1, 
    ...., 
    ...., 
    "user":{ 
      "uid":1, 
      "attr1":"value1", 
      "attr2":"value2", 
      ..... 
      } 
}

問題：org.postgresql.util.PSQLException：我總是得到一個（org.hibernate.exception.SQLGrammarException）誤差（產生的原因：錯誤：在「用戶」或其附近的語法錯誤）

我做錯了什麼？什麼是存儲我的位置的最佳方法？

來源

2014-05-16 Nidhal Rouissi

你可以發佈存儲庫和休眠配置以及 – ikumen

回購配置配置？ –

的例外規定，無效的SQL語句生成

org.postgresql.util.PSQLException: ERROR: syntax error at or near "user"

嘗試將列「用戶」重命名爲「用戶」是Postgres的保留字，所以不是

@JoinColumn(name ="user")

使用像

@JoinColumn(name ="user_location")

來源

2014-05-20 22:13:50 Wilfried

Spring MVC：使用ManyToOne/OneToMany關係存儲數據

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