無法使用PHP發送電子郵件時從MYSQL獲取數據

Question

我正在向我的訂閱者發送電子郵件，並且所有電子郵件地址都被插入到MYSQl的表中。但有了它，我想發送一些位於同一數據庫的其他表中的文章。請幫幫我。在「$ name」中它只提取1行（我想獲取所有給定ID的數據）。

<?php if(isset($_POST['send'])){ 
$servername = "localhost"; 
$username = "username "; 
$password = "password "; 
$dbname = "db"; 

$conn = new mysqli($servername, $username, $password, $dbname); 
if ($conn->connect_error) { 
die("Connection failed: " . $conn->connect_error); 
} 

$sql = "SELECT * FROM table1 where id in (1, 3, 2, 4)"; 
$result = $conn->query($sql); 

if ($result->num_rows > 0) { 
while($row = $result->fetch_assoc()) { 

$name = $row["title"]; 

}}else {} 
$conn->close(); 
} 
?> 

<?php if(isset($_POST['send'])){ 
$servername = "localhost"; 
$username = "username"; 
$password = "password"; 
$dbname = "db"; 

$conn = new mysqli($servername, $username, $password, $dbname); 

if ($conn->connect_error) { 
die("Connection failed: " . $conn->connect_error); 
} 

$sql = "SELECT email, subid FROM table2"; 
$result = $conn->query($sql); 

if ($result->num_rows > 0) {while($row = $result->fetch_assoc()){ 

$subid = $row["subid"]; 

$email_to = $row["email"]; 
$subject = "Newsletter | OnlineDealsIndia"; 
$header = "From: OnlineDealsIndia <noreply@onlinedealsindia.in>\r\n"; 
$header.= "MIME-Version: 1.0\r\n"; 
$header.= "Content-Type: text/html; charset=utf-8\r\n"; 
$header.= "X-Priority: 1\r\n"; 

$message = '<h3>Todays Top Deals!</h3><hr> 

<li>' .$name. '</li> 

<a href="http://www.onlinedealsindia.in/newsletter/unsubscribe/?subid=' .$subid. '">Click Here</a> To Unsubscribe 
'; 
mail($email_to,$subject,$message,$header); 
}}else {} 

$conn->close(); 
} 
?> 

在「$ name」中，它應該獲取上面提供的id的所有行。

所有的答案將不勝感激。謝謝！

Answer 1

這應該做的伎倆：

<?php if (isset($_POST['send'])) { 
    $servername = "localhost"; 
    $username = "username "; 
    $password = "password "; 
    $dbname  = "db"; 

    $conn = new mysqli($servername, $username, $password, $dbname); 
    if ($conn->connect_error) { 
     die("Connection failed: " . $conn->connect_error); 
    } 

    $sql = "SELECT * FROM table1 where id in (1, 3, 2, 4)"; 
    $result = $conn->query($sql); 

    $subject = "Newsletter | OnlineDealsIndia"; 
    $header = "From: OnlineDealsIndia <noreply@onlinedealsindia.in>\r\n"; 
    $header .= "MIME-Version: 1.0\r\n"; 
    $header .= "Content-Type: text/html; charset=utf-8\r\n"; 
    $header .= "X-Priority: 1\r\n"; 

    $message = '<h3>Todays Top Deals!</h3><hr><ul>'; 
    if ($result->num_rows > 0) { 
     while ($row = $result->fetch_assoc()) { 
      $message .= '<li>' . $row["title"] . '</li>'; 
     } 
    } 
    $message .= '</ul><a href="http://www.onlinedealsindia.in/newsletter/unsubscribe/?subid=' . $subid . '">Click Here</a> To Unsubscribe'; 

    $sql = "SELECT email, subid FROM table2"; 
    $result = $conn->query($sql); 

    if ($result->num_rows > 0) { 
     while ($row = $result->fetch_assoc()) { 
      $subid = $row["subid"]; 
      $email_to = $row["email"]; 
      mail($email_to, $subject, $message, $header); 
     } 
    } 

    $conn->close(); 
} 
?>