我在我們的日常時間記錄中對數據進行分組和排序時出現問題以自動生成報告。的DTR爲表結構如下：複雜的SQL排序和分組

 
Log Date Log Time Employee Name   Log Type 
9/13/2012 17:00:00 SALITA, LYNYRD ANTONIO LOGOUT 
9/13/2012 8:05:00  SALITA, LYNYRD ANTONIO LOGIN 
9/12/2012 17:05:00 SALITA, LYNYRD ANTONIO LOGOUT 
9/12/2012 8:05:00  SALITA, LYNYRD ANTONIO LOGIN 
7/10/2012 17:00:00 GARCIA, ALVIN   LOGOUT 
7/10/2012 17:00:00 AURENO, LEAH   LOGOUT 
7/10/2012 17:00:00 SALITA, LYNYRD ANTONIO LOGOUT 
7/10/2012 17:00:00 CANSINO, PAUL   LOGOUT 
7/10/2012 17:00:00 BELO, RIO    LOGOUT 
7/10/2012 17:00:00 MAG-ISA, MAYBELLE  LOGOUT 
7/10/2012 17:00:00 TARINE, KAREN   LOGOUT 
7/10/2012 17:00:00 REYES, ANDREA   LOGOUT 
7/10/2012 17:00:00 NAVARRO, KRISTINA  LOGOUT 
7/10/2012 10:30:00 MAG-ISA, MAYBELLE  LOGIN 
7/10/2012 8:00:00  SALITA, LYNYRD ANTONIO LOGIN 
7/10/2012 8:00:00  CANSINO, PAUL   LOGIN 
7/10/2012 8:00:00  BELO, RIO    LOGIN 
7/10/2012 7:40:00  AURENO, LEAH   LOGIN 
7/10/2012 7:30:00  GARCIA, ALVIN   LOGIN 
7/10/2012 7:25:00  TARINE, KAREN   LOGIN 
7/10/2012 7:10:00  NAVARRO, KRISTINA  LOGIN 
7/10/2012 7:10:00  REYES, ANDREA   LOGIN

我想它要處理的查詢，像這樣的輸出：

 
Log Date Employee Name   LOGIN  LOGOUT 
9/13/2012 SALITA, LYNYRD ANTONIO 8:05:00  17:00:00 
9/12/2012 SALITA, LYNYRD ANTONIO 8:05:00  17:05:00 
7/10/2012 GARCIA, ALVIN   7:30:00  17:00:00 
7/10/2012 AURENO, LEAH   7:40:00  17:00:00 
7/10/2012 SALITA, LYNYRD ANTONIO 8:00:00  17:00:00 
7/10/2012 CANSINO, PAUL   8:00:00  17:00:00 
7/10/2012 BELO, RIO    8:00:00  17:00:00 
7/10/2012 MAG-ISA, MAYBELLE  10:30:00 17:00:00 
7/10/2012 TARINE, KAREN   7:25:00  17:00:00 
7/10/2012 REYES, ANDREA   7:10:00  17:00:00 
7/10/2012 NAVARRO, KRISTINA  7:10:00  17:00:00

如何實現這一目標？

來源

2012-09-13 Lynyrd Salita

Wich RDBMS：MS SQL Server，MySQL，Postgre，Oracle？而且，你有什麼嘗試？發佈一個工作查詢，不管其錯誤，也許你只是一步接近解決方案 – Yaroslav

這是你試圖讓：

使用CASE聲明，以行轉換爲列（Login和Logout：

SELECT DATE_FORMAT(LogDate, '%d/%c/%Y') AS LogDate, EmployeeName, 
    (GROUP_Concat(CASE LogType WHEN 'LOGIN' THEN LogTime END)) AS LOGIN, 
    (GROUP_Concat(CASE LogType WHEN 'LOGOUT' THEN LogTime END)) AS LOGOUT 
FROM myTable 
GROUP BY LogDate, EmployeeName 
ORDER BY LogDate desc;

See this SQLFiddle

查詢說明）

SELECT DATE_FORMAT(LogDate, '%d/%c/%Y') AS LogDate, EmployeeName, 
    (CASE LogType WHEN 'LOGIN' THEN LogTime END) AS LOGIN, 
    (CASE LogType WHEN 'LOGOUT' THEN LogTime END) AS LOGOUT 
FROM myTable 
GROUP BY LogDate, EmployeeName, LogTime 
ORDER BY LogDate desc;

但這會導致你喜歡in this SQLFiddle.

所以你需要使用GROUP_CONCAT（MySQL的）加入LogTime與NULL和GROUP BY條款刪除LogTime。

來源

2012-09-13 08:22:36 hims056

thnx解決了這個問題。我只需要校準變量！ thnx再次！ –

有沒有辦法只顯示第一次登錄和最後登錄？ –

@LynyrdSalita無法理解你的句子'只顯示第一次登錄和最後登錄'。你能顯示你想要的輸出嗎？ – hims056

Select Log Date, Employee Name,  LOGIN  LOGOUT 
    case(Log Type) 
    when 'LOGIN' then Log Time AS LOGIN 
    Else 
    Log Time AS LOGOUT 
    End 
From 
YOUR_TABLE 
order by Log Date desc

來源

2012-09-13 08:05:44 levi

複雜的SQL排序和分組

回答

See this SQLFiddle

相關問題