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iam需要從數據庫中獲取數據具有相同name.i使用json數組來獲得輸出。json數組在codeigniter
function search_review($input, $serviceName){
$data = array();
$ipJson = json_encode($input);
$this->db->select('*');
$this->db->from('reviews');
$this->db->where('reviewee_name', $input['reviewee_name']);
$query = $this->db->get();
$result = $query->result();
if (!empty($result)) {
foreach ($query->result() as $row)
{
$data[]['reviewer_id'] = $row->reviewer_id;
$data[]['reviewee_name'] = $row->reviewee_name;
$data[]['tournament_played_c_s'] = $row->tournament_played_c_s;
}
$data['message'] = 'Review details retrieved successfully.';
$status = $this->clamo_lib->return_status('success', $serviceName, $data, $ipJson);
} else {
$data['message'] = 'Unable to retrieve review details.';
$status = $this->clamo_lib->return_status('error', $serviceName, $data, $ipJson);
}
return $status;
}
0utput:
我需要讓我的輸出
<data>
<_0/>
<message>Review details retrieved successfully.</message>
<reviewee_name>deepi</reviewee_name>
<reviewer_id>4</reviewer_id>
<tournament_played_c_s>karnataka,bangalore</tournament_played_c_s>
</data>
<data>
<_1/>
<message>Review details retrieved successfully.</message>
<reviewee_name>deepi</reviewee_name>
<reviewer_id>5</reviewer_id>
<tournament_played_c_s>kerala</tournament_played_c_s>
</data>
我在這個改變?
<_0> 3 reviewer_id> <_1> deepi reviewee_name> <_2> 奈,TN tournament_played_c_s> <_3> 4 reviewer_id> <_4> deepi reviewee_name> <_5> 卡納,班加羅爾 tournament_played_c_s> 評分細節成功檢索。 –
sangee
現在我正在得到這樣的輸出? – sangee
什麼是$ this-> clamo_lib?我們可以看到它的代碼嗎?這看起來像XML不JSON ... – Jon