如何初始化nsstring的值？

Question

目前即時加載我的聲音與

NSString * strName = [NSString stringWithFormat:@"soundpack%ld", (long) (value+1)]; 

以獲得每個聲音的值。現在我想把它從數組中拉出來。看起來是這樣的：

NSMutableArray * sounds = [NSMutableArray arrayWithObjects: @"soundpack1", @"soundpack2", @"soundpack3", @"soundpack4", @"soundpack5", @"soundpack6", @"soundpack7", @"soundpack8", @"soundpack9", nil]; 
    NSUInteger count = [sounds count]; 

    for (NSUInteger i = 0; i < count; ++i) { 
     NSInteger nElements = count - i; 
     NSInteger n = arc4random_uniform((u_int32_t)nElements) + i; 
     [sounds exchangeObjectAtIndex:i withObjectAtIndex:n]; 
    } 
    NSString * strName0 = [sounds objectAtIndex:1]; 

好了，現在我已經洗牌的聲音，現在我想初始化像以前那樣有具體的值。

類似：

NSString * strName = [sounds objectAtIndex:%ld, (long) (value+1)]; 

或

NSString * strName = [sounds objectAtIndex:@"%ld", (long) (value+1)]; 

沒有工作。但我不知道，現在該怎麼辦...

Answer 1

嘗試將此行

NSString * strName = [sounds objectAtIndex:@"%ld", (long) (value+1)];

改變

NSString * strName = [sounds objectAtIndex:(long) (value+1)];

Answer 2

爲什麼你不要在洗牌後使用相同的片段？

NSString * strName = [NSString stringWithFormat:@"soundpack%ld", (long) (value+1)];