用MySQL中的兩個表選擇

Question

我有兩個表hits和posts。在hits表我有id_post,hits和posts表我有id,title

我需要建立與相關的命中和爲了通過點擊所有帖子的報告。任何人都可以幫我選擇？

感謝

Answer 1

SELECT posts.id, posts.title, hits.hits 
FROM  posts LEFT JOIN hits ON hits.id_post = posts.id 
ORDER BY hits.hits 

Answer 2

SELECT posts.id as id, posts.title as title, hits.hits as hitsdate 
FROM  posts INNER JOIN hits ON hits.id_post = posts.id 
ORDER BY hits.hits 

Answer 3

試試這個

$q=mysql_query("SELECT * FROM `posts` ORDER BY `title`;"); 
while($qresult=mysql_fetch_array($q)) 
{ 
    $post_id=$qresult['id']; 
    $post_title=$qresult['title']; 
    $hitsretreiver=mysql_query("SELECT * FROM `hits` WHERE `id_post`='$post_id';") 
    while($hitsretreiverresult=mysql_fetch_array($hitsretreiver) 
    { 
     $relatd_hit=$hitsretreiverresult['hits']; 
     echo $post_title; 
     echo $relatd_hit; 
    } 
} 

在此代碼你在表後的每個記錄

，你會得到從表命中具有相同ID的記錄