的Symfony2 + Doctrine2：實體去除效果集合

Question

背景信息

我有一個名爲年報與多個集合的實體（假設2爲簡潔的緣故）。的這些集合的一個排在FormType自動處理：

 //AnnualReportStaffing entity collection 
     ->add('staffingTenured', 'collection', array(
      'type' => new AnnualReportStaffingType(), 
      'allow_add' => true, 
      'allow_delete' => true, 
      'by_reference' => false, 
     )) 

的其他集合是文件和刪除的集合不是自動處理：

 //AnnualReportDetail entity collection 
     ->add('documents', 'collection', array(
      'type' => new AnnualReportDocumentType(), 
      'allow_add' => true, 
      'allow_delete' => false, // Do NOT automatically remove documents not in the collection (i.e. edit form where Documents are not passed again) 
      'by_reference' => false, 
     )) 

這是我的AnnualReport實體類中每個集合的屬性/方法聲明：

/** 
* @ORM\ManyToMany(targetEntity="AnnualReportStaffing", cascade={"persist", "detach", "remove"}, orphanRemoval=true, fetch="LAZY") 
* @ORM\JoinTable(name="annualreports_staffingtenure", 
*  joinColumns={@ORM\JoinColumn(name="annualreport_id", referencedColumnName="id")}, 
*  inverseJoinColumns={@ORM\JoinColumn(name="staffing_id", referencedColumnName="id", onDelete="CASCADE")}, 
*  ) 
*/ 
private $staffingTenured; 

/** 
* @ORM\ManyToMany(targetEntity="Document", cascade={"persist", "detach", "remove"}, orphanRemoval=true, fetch="LAZY") 
* @ORM\JoinTable(name="annualreports_documents", 
*  joinColumns={@ORM\JoinColumn(name="annualreport_id", referencedColumnName="id")}, 
*  inverseJoinColumns={@ORM\JoinColumn(name="document_id", referencedColumnName="id", onDelete="CASCADE")}, 
*  ) 
*/ 
private $documents; 

public function __construct(AnnualReportUnit $unit, $year) { 
    $this->staffingTenured = new ArrayCollection(); 
    $this->documents = new ArrayCollection(); 
} 

/** 
* Add staffingTenured 
* 
* @param AppBundle\Entity\AnnualReportStaffing $staffing 
* @return AnnualReport 
*/ 
public function addStaffingTenured(AnnualReportStaffing $staffing) 
{ 
    $this->staffingTenured->add($staffing); 

    return $this; 
} 

/** 
* Remove staffingTenured 
* 
* @param AppBundle\Entity\AnnualReportStaffing $staffing 
* @return AnnualReport 
*/ 
public function removeStaffingTenured(AnnualReportStaffing $staffing) 
{ 
    $this->staffingTenured->removeElement($staffing); 

    return $this; 
} 

/** 
* Get staffingTenured 
* 
* @return ArrayCollection 
*/ 
public function getStaffingTenured() 
{ 
    return $this->staffingTenured; 
} 

/** 
* Add document 
* 
* @param AppBundle\Entity\AnnualReportDocument $document 
* @return AnnualReport 
*/ 
public function addDocument(AnnualReportDocument $document) 
{ 
    $this->documents->add($document); 

    return $this; 
} 

/** 
* Remove document 
* 
* @param AppBundle\Entity\AnnualReportDocument $document 
* @return AnnualReport 
*/ 
public function removeDocument(AnnualReportDocument $document) 
{ 
    $this->documents->removeElement($document); 

    return $this; 
} 

/** 
* Get documents 
* 
* @return ArrayCollection 
*/ 
public function getDocuments() 
{ 
    return $this->documents; 
} 

問題

當談到時間刪除年報實體：

• 如果文件存在，我能夠刪除的文件集合，但我得到了一個外鍵約束錯誤員工保險項目。

An exception occurred while executing 'DELETE FROM annual_report WHERE id = ?' with params [57]: 

SQLSTATE[23000]: Integrity constraint violation: 1451 Cannot delete or update a parent row: a foreign key constraint fails 

（libcommand。annualreports_staffingtenure，約束 FK_DB56517AD4F67A27外鍵（annualreport_id）參考文獻 annual_report（id））

• 如果沒有文件都存在，年報實體和所有人員配備保密項目按預期被刪除。

這是deleteAction（）：

public function deleteAction(Request $request, $id) 
{ 
    $requestData = $request->request->all(); 
    $unit = $requestData['form']['unit']; 


    $form = $this->createDeleteForm($id); 
    $form->handleRequest($request); 

    if ($form->isValid()) { 
     $em = $this->getDoctrine()->getManager(); 
     $entity = $em->getRepository('AppBundle:AnnualReport')->find($id); 

     if (!$entity) { 
      throw $this->createNotFoundException('Unable to find AnnualReport entity.'); 
     } 

     //Remove any documents (allow_delete set to FALSE in form so have to do manually) 
     $documents = $entity->getDocuments(); 
     foreach($documents as $document){ 
      $entity->removeDocument($document); 
      //$em->remove($document); 
     } 
     $em->persist($entity); 
     $em->flush(); 

     $em->remove($entity); 
     $em->flush(); //flush again to remove the annual report 
    } 

    return $this->redirect($this->generateUrl('annualreportunit_edit', array('id' => $unit))); 
} 

Answer 1

您在這裏混合形式和ORM。 allow_delete是表單的參數，這意味着它用於處理表單。

因爲symfony的doc說的allow_delete：

如果設置爲true，那麼如果現有的項目沒有在提交的數據包含，這將是從項目的最終陣列正確地缺席。 這意味着你可以通過JavaScript實現一個「刪除」按鈕，它只是從DOM中刪除一個表單元素。當用戶提交表單時，它不在提交的數據中意味着它從最終數組中移除。

因此，它可以用來實現以的形式從根實體中移除收集項的可能性。但這並不意味着教義也會神奇地處理它。

如果您希望子實體在父實體時被保存/刪除，您應該使用cascade屬性中的實體映射。

Answer 2

你如何捕捉ForeignKeyConstraintViolationException異常或更好的捕獲DBALException。然後向用戶顯示錯誤。或者當您捕獲異常時，您可以刪除子節點，然後再次刪除該實體。

use Doctrine\DBAL\Exception\ForeignKeyConstraintViolationException;
或者
use Doctrine\DBAL\DBALException;

try { 
    $em->remove($entity); 
    $em->flush(); 

    $this->addFlash('success', 'Removed'); 
} catch (DBALException $e) { 
    $em->remove($childEntity); 
    $em->flush(); 

    $em->remove($entity); 
    $em->flush(); 
--OR-- 
} catch (ForeignKeyConstraintViolationException $e) { 
    $em->remove($childEntity); 
    $em->flush(); 

    $em->remove($entity); 
    $em->flush(); 
}