根據特定日期範圍在一個月內彙總多個列

Question

我需要彙總Amounts以按月份的日期範圍顯示。爲了說明請大家看看下面的表中：

Invoice_Payment

Customer_id Invoice_no Invoice_date Amount 
--------------------------------------------------- 
10    10023   2016-07-08  60 
10    10018   2016-08-04  90 
11    10016   2016-07-01  110 
11    10021   2016-07-05  120 
12    10028   2016-07-11  10 
12    10038   2016-07-31  5 

正如您看到的，我想他們基於Customer_id組和從頭到尾顯示的日期。此外，這隻能在每個月進行。

下面的查詢到目前爲止，我曾嘗試：

select Customer_id, (mindate + ' to ' + maxdate) Date_Range, Amount 
from (
    select Customer_id, sum(Amount) Amount, min(Invoice_date) mindate, max(Invoice_date) maxdate 
    from Invoice_Payment 
    group by Customer_id 
    ) I ; 

從上面查詢我越來越喜歡Output：

Customer_id Date_Range     Amount 
10    2016-07-08 to 2016-08-04  150 
11    2016-07-01 to 2016-07-05  230 
12    2016-07-11 to 2016-07-31  15 

請檢查這個.. SQL Fiddle Working Demo

比方說， Customer_id = 10誰在July,2016和中有Invoice_date。我需要在特定日期範圍內分別總結該特定客戶在七月份和八月份的所有付款。但是我從上面的努力獲得所有Invoice_date的Amount的總和。

所需的輸出：

Customer_id Date_Range     Amount 
10    2016-07-08 to 2016-07-08  60 
10    2016-08-04 to 2016-08-04  90 
11    2016-07-01 to 2016-07-05  230 
12    2016-07-11 to 2016-07-31  15 

我怎麼能渡過這個？任何幫助將不勝感激。

Answer 1

快要大功告成。只需添加YEAR和MONTH至GROUP BY即可。

select Customer_id, (mindate + ' to ' + maxdate) Date_Range, Amount 
from (
     select Customer_id, 
     sum(Amount) Amount, min(Invoice_date) mindate, max(Invoice_date) maxdate 
     from #Invoice_Payment 
group by 
    Customer_id, 
    YEAR(Invoice_date), 
    MONTH(Invoice_date) 
) I ; 

Answer 2

如何逐年CUSTOMER_ID，一個月分組和

select Customer_id, (mindate + ' to ' + maxdate) Date_Range, Amount 
from (
     select Customer_id, 
     sum(Amount) Amount, min(Invoice_date) mindate, max(Invoice_date) maxdate 
     from #Invoice_Payment 
     group by Customer_id,month(Invoice_date), year(Invoice_date) 
) I 
order by customer_id;