如何在C++中使用組合作爲用戶輸入「cin」

Question

我有三個C++類，InventoryItem，SalesPerson和Transaction。我正在使用組合在Transaction中使用InventoryItem和SalesPerson類。我想使用用戶輸入，而不是在構造函數中傳遞值，但我無法做到這一點。任何幫助將不勝感激。以下是我的C++文件。

#include<iostream> 
    #include<string> 
    using namespace std; 

    class InventoryItem { 
    private: 
     int stockNum; double price; 
    public: 
     InventoryItem(int, double); 
     void display(); }; 
    InventoryItem::InventoryItem(int stkNum, double pr) { 
     stockNum = stkNum; 
     price = pr; 
    } 
    void InventoryItem::display() { 
     cout << "Item #" << stockNum << " costs $" << price << endl; 
    } 

    //SalesPerson class 
    class Salesperson { 
    private: 
     int idNum; 
     string name; public: 
     Salesperson(int, string); void display(); 
    }; 
    Salesperson::Salesperson(int id, string lastName) { 
     idNum = id; 
     name = lastName; 
    } 
    void Salesperson::display() { 
     cout << "Salesperson #" << idNum << " " << name << endl; 
    } 

    //Transaction(main class) 
    class Transaction { 
    private: 
     int transNum; 
     InventoryItem itemSold; 
     Salesperson seller; 
    public: 
     Transaction(int, int, double, int, string); 
     void display(); 
    }; 
    Transaction::Transaction(int num, int item, double pr, 
          int salesId, string name) : itemSold(item, pr), 
     seller(salesId, name) { 
     transNum = num; 
    } 
    void Transaction::display() { 
     cout << "Data for transaction #" << transNum << endl; itemSold.display(); 
     seller.display(); 
    } 
    int main() { 
     Transaction aSale(247, 782, 44.77, 512, "Richardson"); aSale.display(); 
     return 0; 
    } 

Answer 1

我張貼此答案而不是評論，因爲我沒有在我的手機上反引號。所以，你要像做

int main() 
{ 
    int x, y, z; 
    double f; 
    string name; 

    cin >> x >> y >> f >> z >> name; 

    Transaction(x, y, f, z, name); 
    return 0; 
} 

當然，你可以把cin行成一個cin每個變量和cout說明什麼，用戶必須輸入下一個。這看起來像cout線，串要提示與用戶這

int main() 
{ 
    int x, y, z; 
    double f; 
    string name; 

    cout << "Enter x: "; 
    cin >> x; 
    cout << "Enter y: "; 
    cin >> y; 
    cout << "Enter f: "; 
    cin >> f; 
    cout << "Enter z: "; 
    cin >> z; 
    cout << "Enter name: "; 
    cin >> name; 

    Transaction(x, y, f, z, name); 
    return 0; 
} 

替換字符串。