SQL和ALL操作

Question

尋找一個優雅的方式來解決這個...

DECLARE @ZIP INT 
SET @ZIP = 55555 

IF @ZIP = ALL(SELECT ZIP FROM PEOPLE WHERE PERSONTYPE = 1) 
    PRINT 'All people of type 1 have the same zip!' 
ELSE 
    PRINT 'Not All people of type 1 have the same zip!' 

的問題是，如果（選擇ZIP從不同人的PERSONTYPE = 1）返回任何記錄，那麼上面的if計算爲真。我正在尋找一種方法，當ALL的子查詢沒有返回任何記錄時，將其評估爲false。

我目前的解決方案：

DECLARE @ZIP INT 
SET @ZIP = 55555 

DECLARE @ALLZIPS TABLE (INT ZIP) 

INSERT INTO @ALLZIPS 
SELECT ZIP FROM PEOPLE WHERE PERSONTYPE = 1 

IF EXISTS(SELECT TOP 1 * FROM @ALLZIPS) AND (@ZIP = ALL (SELECT ZIP FROM @ALLZIPS)) 
    PRINT 'All people of type 1 have the same zip!' 
ELSE 
    PRINT 'Not All people of type 1 have the same zip!' 

Answer 1

跳躍：

IF (SELECT SUM(CASE WHEN ZIP = @ZIP THEN 0 ELSE 1 END) 
    FROM PEOPLE WHERE PERSONTYPE = 1) = 0 
    PRINT 'All people of type 1 have the same zip!' 
ELSE 
    PRINT 'Not All people of type 1 have the same zip!' 

Answer 2

考慮使用中也存在。

IF @ZIP = ALL(SELECT ZIP FROM PEOPLE WHERE PERSONTYPE = 1) 
    AND EXISTS(SELECT 1 FROM PEOPLE WHERE PERSONTYPE = 1) 

Answer 3

用途：

IF EXISTS(SELECT NULL 
      FROM PEOPLE p 
      WHERE p.persontype = 1 
      HAVING MIN(p.zip) = @Zip 
      AND MAX(p.zip) = @Zip) 
    PRINT 'All people of type 1 have the same zip!' 
ELSE 
    PRINT 'Not All people of type 1 have the same zip!'