2014-09-29 52 views
1

如果我的查詢字符串與我指定的表的列值匹配,我有一個數據庫,我想要更改某個表的行值的狀態..嘗試在MySQL查詢中使用多個WHERE命令[Not Working]

這是我迄今爲止所做的...

<?php 

$connection = mysql_connect("localhost", "creative_db", "samplepassword"); 
$db = mysql_select_db("creative_dbgogo", $connection); 

$slct = mysql_query("UPDATE zombie_links SET link_status = 'discard' WHERE link_url = '%pills%' OR link_url_title = '%pills%' OR link_title = '%pills%' OR link_title_url = '%pills%' OR link_content = '%pills%' OR link_summary = '%pills%' OR link_tags= '%pills%' ") or die(mysql_error()); 

?> 

我在做什麼錯?請幫忙!

+1

你不說是什麼問題,你遇到。 – arkyc 2014-09-29 02:52:07

+0

@arkyc問題是,沒有錯誤正在顯示,也沒有在我的數據庫上工作.. – Swayam 2014-09-29 16:00:01

回答

1

=不採用通配符。我想你想要like

UPDATE zombie_links 
    SET link_status = 'discard' 
    WHERE link_url like '%pills%' OR link_url_title like '%pills%' OR link_title like '%pills%' OR 
      link_title_url like '%pills%' OR link_content like '%pills%' OR 
      link_summary like '%pills%' OR link_tags like '%pills%'; 
+0

謝謝! :-) 有效!! :-) – Swayam 2014-09-29 16:08:14

0

試試這個

$slct = mysql_query("UPDATE zombie_links SET link_status = 'discard' WHERE link_url like '%pills%' OR link_url_title like '%pills%' OR link_title like '%pills%' OR link_title_url like '%pills%' OR link_content like '%pills%' OR link_summary like '%pills%' OR link_tags like '%pills%' ") or die(mysql_error()); 
+0

感謝:-)它工作! – Swayam 2014-09-29 16:07:55

+0

如果它是值得的,請接受並注意 – ashokhein 2014-09-29 16:26:33