1
我正在用Hibernate Search 4.5.1和Spring 4.0.5.RELEASE構建一個應用程序。我試圖索引以下類：Hibernate搜索沒有返回結果
@Entity
@Indexed
@Analyzer(impl= org.apache.lucene.analysis.standard.StandardAnalyzer.class)
@Table(name="SONG")
@XmlRootElement(name="song")
public class Song
{
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "ID", updatable = false, nullable = false)
private Long id;
@Field(store = Store.YES)
@Column(name="NAME", length=255)
private String name;
@Field(store = Store.YES)
@Column(name="ALBUM", length=255)
private String album;
@Field(store = Store.YES)
@Column(name="ARTIST", length=255)
private String artist;
@NotNull
@Column(name="PATH", length=255)
private String path;
@NotNull
@Column(name="PATH_COVER", length=255)
private String cover;
@NotNull
@Column(name="LAST_VOTE")
private Date date;
@Field(store = Store.YES)
@NotNull
@Column(name="N_VOTES")
private int nvotes;
@NotNull
@Column(name="ACTIVE", nullable=false, columnDefinition="TINYINT(1) default 0")
private boolean active;
@OneToOne(fetch=FetchType.LAZY)
@JoinColumn(name="IMAGE_ID",insertable=true,updatable=true,nullable=false,unique=false)
private Image image;
@IndexedEmbedded
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "PLAYLIST_ID", nullable = false)
private PlayList playList;
@OneToMany(mappedBy = "song")
private Set<UserVotes> userServices = new HashSet<UserVotes>();
我建立一個JUnit測試案例，看起來像這樣：
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations = {"classpath:jukebox-servlet-test.xml"})
@Transactional
public class SongDaoTest {
@Autowired
public I_PlaceDao placeDao;
@Autowired
public I_PlayListDao playListDao;
@Autowired
public I_SongDao songDao;
@Before
public void prepare() throws Exception
{
Operation operation = sequenceOf(CommonOperations.DISABLE_CONTRAINTS, CommonOperations.DELETE_ALL,CommonOperations.INSERT_SONG_DATA, CommonOperations.ENABLE_CONTRAINTS);
DbSetup dbSetup = new DbSetup(new DriverManagerDestination("jdbc:mysql://localhost:3306/jukebox", "root", "mpsbart"), operation);
dbSetup.launch();
FullTextSession fullTextSession = Search.getFullTextSession(placeDao.getSession());
fullTextSession.createIndexer().startAndWait();
}
@Test
@Rollback(false)
public void searchTest()
{
PlayList playList = playListDao.read(1l);
List<Song> songs = songDao.search(playList, "offspring", 1, 10);
assertEquals(10, songs.size());
}
的搜索方法實現：
@SuppressWarnings("unchecked")
public List<Song> search(PlayList playlist, String searchTerm,int page,int limit)
{
FullTextSession fullTextSession = Search.getFullTextSession(getSession());
QueryBuilder queryBuilder = fullTextSession.getSearchFactory().buildQueryBuilder().forEntity(Song.class).get();
BooleanQuery luceneQuery = new BooleanQuery();
luceneQuery.add(queryBuilder.keyword().onFields("name","album","artist").matching("*"+searchTerm+"*").createQuery(), BooleanClause.Occur.MUST);
luceneQuery.add(queryBuilder.phrase().onField("playList.place.id").sentence("\""+playlist.getPlace().getId()+"\"").createQuery(), BooleanClause.Occur.MUST);
luceneQuery.add(queryBuilder.phrase().onField("playList.id").sentence("\""+playlist.getId()+"\"").createQuery(), BooleanClause.Occur.MUST);
// wrap Lucene query in a javax.persistence.Query
FullTextQuery query = fullTextSession.createFullTextQuery(luceneQuery, Song.class);
org.apache.lucene.search.Sort sort = new Sort(new SortField("n_votes",SortField.INT));
query.setSort(sort);
List<Song> songs = query.setFirstResult(page*limit).setMaxResults(limit).list();
return songs;
}
測試結果失敗，它沒有找到任何匹配的對象。當使用luke lucene時，我可以看到有結果，如果我嘗試在luke上通過休眠生成的查詢，它會返回元素。由Hibernate生成的查詢是：+（名稱：Metallica的專輯：Metallica的藝術家：METALLICA）+ playList.place.id：」 「+ playList.id：」 1"
我也注意到了盧克的Lucene某些索引術語的長度最多可達六個字符，例如，一首歌曲的藝術家是「The Offspring」，索引中存儲的術語是「the」和「offspr」。第一個沒關係，但不應該第二個是「後代」。爲什麼會截斷這個名字？