使用sed在兩種模式之間打印

Question

所以我發現很多deleting the text between two patterns和printing the text between two delimiters，但是我還沒有發現使用bash函數在兩個模式之間打印文本的任何內容。

如果我有：

"Alas poor Yorik, I knew him well" 

，我想模式之間打印一切「窮」與「井」（獨家）我會得到：

" Yorik, I knew him " 

我怎麼能做到這一點使用類似sed或awk的東西？

Answer 1

dtpwmbp:~ pwadas$ echo "Alas poor Yorik, I knew him well" | sed -e 's/^.*poor //g;s/ well.*$//g' 
Yorik, I knew him 
dtpwmbp:~ pwadas$ echo "Alas poor Yorik, I knew him well" | awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' 
Yorik, I knew him 

用法與文件輸入：

dtpwmbp:~ pwadas$ echo "Alas poor Yorik, I knew him well" > infile 
dtpwmbp:~ pwadas$ cat infile 
Alas poor Yorik, I knew him well 
dtpwmbp:~ pwadas$ cat infile | sed -e 's/^.*poor //g;s/ well.*$//g' 
Yorik, I knew him 
dtpwmbp:~ pwadas$ sed -e 's/^.*poor //g;s/ well.*$//g' < infile 
Yorik, I knew him 
dtpwmbp:~ pwadas$ cat infile | awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' 
Yorik, I knew him 
dtpwmbp:~ pwadas$ awk '{sub(/.*poor /,"");sub(/ well.*/,"");print;}' < infile 
Yorik, I knew him