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就這樣,根據我最後一個問題here我之一finnaly想出了這個查詢,基本上拉的任何用戶,在任何24小時的時間內超過100次下載。mysql在時間跨度查詢優化之間進行選擇
SELECT *,
users.userid AS IP,
MAX(ucount)
FROM (SELECT t1.user_id,
t1.data DE,
ADDTIME(t1.data,'24:00:00') A,
(SELECT COUNT(1)
FROM downloads t2
WHERE t1.user_id = t2.user_id
AND t1.data <= t2.data
AND ADDTIME(t1.data,'24:00:00') >= t2.data) ucount
FROM downloads t1) t3
LEFT JOIN users ON users.id = t3.user_id
WHERE ucount > 100
GROUP BY IP
的是,具有〜40K記錄和用戶表〜9K區域經濟共同體,這是我所得到的性能明智的下載表格:
8 rows in set (9.18 sec)
對於這個問題的,解釋來liek這
+----+--------------------+------------+--------+---------------+---------+---------+-----------------------+-------+----------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+--------------------+------------+--------+---------------+---------+---------+-----------------------+-------+----------------------------------------------+
| 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 38949 | Using where; Using temporary; Using filesort |
| 1 | PRIMARY | users | eq_ref | PRIMARY | PRIMARY | 4 | t3.user_id | 1 | |
| 2 | DERIVED | t1 | ALL | NULL | NULL | NULL | NULL | 38949 | |
| 3 | DEPENDENT SUBQUERY | t2 | ref | users,data | users | 4 | admin_beta.t1.user_id | 5 | Using where |
+----+--------------------+------------+--------+---------------+---------+---------+-----------------------+-------+----------------------------------------------+
4 rows in set (8.90 sec)
我該如何改進這樣的查詢?
它可以節省〜1秒;但它會超過一秒,因爲它增長我猜... ...暫時是我的最佳拍攝! – eduardev 2011-02-01 18:49:42