當上提交按鈕,Ajax的工作原理,並呼籲PHP頁面(不刷新)點擊,但是當按下輸入該refreshs頁面和腳本無法正常工作,只有?txtname=(INPUTED TEXT)
出現在頁面網址的結尾。不同的行爲,並輸入
Ajax代碼:
var time_variable;
var root2 = location.protocol + '//' + location.host + '/testing.php';
function getXMLObject() //XML OBJECT
{
var xmlHttp = false;
try {
xmlHttp = new ActiveXObject("Msxml2.XMLHTTP") // For Old Microsoft Browsers
}
catch (e) {
try {
xmlHttp = new ActiveXObject("Microsoft.XMLHTTP") // For Microsoft IE 6.0+
}
catch (e2) {
xmlHttp = false // No Browser accepts the XMLHTTP Object then false
}
}var root = location.protocol + '//' + location.host;
if (!xmlHttp && typeof XMLHttpRequest != 'undefined') {
xmlHttp = new XMLHttpRequest(); //For Mozilla, Opera Browsers
}
return xmlHttp; // Mandatory Statement returning the ajax object created
}
var xmlhttp = new getXMLObject(); //xmlhttp holds the ajax object
function ajaxFunction() {
var getdate = new Date(); //Used to prevent caching during ajax call
if(xmlhttp) {
var txtname = document.getElementById("txtname");
xmlhttp.open("POST",root2,true); //calling testing.php using POST method
xmlhttp.onreadystatechange = handleServerResponse;
xmlhttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
xmlhttp.send("txtname=" + txtname.value); //Posting txtname to PHP File
}
}
function handleServerResponse() {
if (xmlhttp.readyState == 4) {
if(xmlhttp.status == 200) {
document.getElementById("message").innerHTML=xmlhttp.responseText; //Update the HTML Form element
}
else {
alert("Error during AJAX call. Please try again");
}
}
}
HTML的一部分:
<body>
<form name="myForm">
<table>
<tr>
<td>Enter Name</td>
<td><input type="text" name="txtname" id="txtname" value="<?php echo $f ?>" /></td>
</tr>
<tr>
<td colspan="2"><input type="button" value="Submit" onclick="ajaxFunction();" /></td>
</tr>
</table>
</form>
<div id="message" name="message"></div>
</body>
請停止安裝活動在HTML標籤通過屬性。 –
它看起來像表單正在提交輸入新聞。這不應該發生,因爲您的輸入類型是按鈕而不是提交。嘗試把表單的返回false onSubmit方法。 –
您是否知道'XMLHTTP =新的ActiveXObject(「MSXML2.XMLHTTP」)//舊微軟Browsers'指的是IE5和IE5.5 .. EMM ..你確定這是你的初衷,或者只是一個不好的情況下複製粘貼? –