使用來自兩個不同while循環的變量

Question

如何使用來自不同while循環的變量並將它們插入到打印語句中？

public class Squares{ 
    public static void main (String [] args){ 
     int counterA = 0; 
     int counterB= 0; 

     while (counterA<51){ 
      counterA++; 
      if (counterA % 5 == 0){ 
       int one = (counterA*counterA); 
      }    
     } 
     while (counterB<101){ 
      counterB++; 
      if (counterB % 2 == 0){ 
       int two = (counterB*counterB);   
      }  
     } 
     System.out.println(one+two); 
    } 
} 

Answer 1

需要聲明環路外的局部變量一個和兩個

public class Squares{ 
    public static void main (String [] args){ 
     int counterA = 0; 
     int counterB= 0; 
     int one=0; 
     int two=0; 

     while (counterA<51){ 
      counterA++; 
      if (counterA % 5 == 0){ 
       one = (counterA*counterA); 
      }    
     } 
     while (counterB<101){ 
      counterB++; 
      if (counterB % 2 == 0){ 
       two = (counterB*counterB);   
      }  
     } 
     System.out.println(one+two); 
    } 
} 

Answer 2

這是相當廣泛的，因爲有很多方法可以做到這一點。您只需要將循環內的結果收集到全局變量中。如果你想專門製作一個字符串，那麼你可以使用類似StringBuilder的東西。

這裏是與數字之間沒有空格的例子：

StringBuilder sb = new StringBuilder(); 
int counterA = 0; 
int counterB = 0; 

while (counterA < 51) { 
    counterA++; 
    if (counterA % 5 == 0){ 
    sb.append(counterA * counterA); 
    }    
} 
while (counterB<101) { 
    counterB++; 
    if (counterB % 2 == 0) { 
    sb.append(counterB * counterB);   
    }  
} 
System.out.println(sb.toString()); 

你也可以把變量分爲數組，等：

ArrayList<Integer> list = new ArrayList<Integer>(); 
while (counterA < 51) { 
    counterA++; 
    if (counterA % 5 == 0){ 
    list.add(counterA * counterA); 
    }    
} 

Answer 3

聲明變量，你的循環之外，併爲它們分配的循環內的值！

Answer 4

我覺得這是你的答案

public class Squares{ 
public static void main (String [] args){ 
    int counterA = 0; 
    int counterB= 0; 

    while (counterA<101){ 
     counterA++; 
     int one,two; 
     if (counterA % 5 == 0){ 
      one = (counterA*counterA); 
     }    
     if (counterA % 2 == 0){ 
      two = counterA * counterA; 
     } 
     System.out.println(ont + two); 
    } 
} 
}