將隨機生成的值鏈接到列表對象

Question

我正在使用以下代碼來生成隨機顏色。

static Color[] colors = { Color.Red, Color.Green, Color.Yellow}; 
static Color GetRandomColor() 
{ 
    var random = new Random(); 
    return colors[random.Next(colors.Length)]; 
} 

現在我需要關聯到用戶的列表：

 List<Utente> ListaUtente = new List<Utente>(); 
     ListaUtente.Add(new Utente(22, "Pedro", 555444333, "pedro@gmail.com")); 
     ListaUtente.Add(new Utente(22, "Lucas", 555444333, "lucas91@gmail.com")); 
     ListaUtente.Add(new Utente(22, "Rodrigo", 555444333, "rodrigo00@gmail.com")); 
     ListaUtente.Add(new Utente(22, "Gaspar", 555444333, "gaspar@gmail.com")); 
     ListaUtente.Add(new Utente(22, "Assis", 555444333, "assis@gmail.com")); 

並在屏幕上一樣顯示出來：用戶1 - 紅， 用戶2 - 格林等

什麼最簡單的方法來做到這一點？我不知道如何連接這兩個代碼塊。只是爲了給你一些背景我在做一個醫院管理服務，我需要爲每個用戶分配一個緊急顏色。

Answer 1

public class Person 
{ 
    public int Id { get; set; } 
    public string Name { get; set; } 
    public string Color { get; set; } 
} 
public class Colours 
{ 
    public string ColourName { get; set; } 
} 

class Program 
{ 
    static void Main(string[] args) 
    { 

     List<Person> People = new List<Person>() 
     { 
      new Person { Id = 1, Name = "Dave" }, 
      new Person { Id = 2, Name = "Joe" }, 
      new Person { Id = 3, Name = "Stephen"}, 
      new Person { Id = 4, Name = "Sue" }, 
      new Person { Id = 5, Name = "Jemma" }, 
      new Person { Id = 6, Name = "Sharon" }, 
     }; 
     Dictionary<int, Colours> Colours = new Dictionary<int, Colours>() 
     { 
      { 1, new Colours { ColourName = "Color.Red" }}, 
      { 2, new Colours { ColourName = "Color.Green"}}, 
      { 3, new Colours { ColourName = "Color.Blue"}}, 
     }; 

     Random RandomNumber = new Random(); 

     int ListPostionToRemoveAt = RandomNumber.Next(1, People.Count); 
     int RandomColourPostion = RandomNumber.Next(1, Colours.Count); 

     Person p = People[ListPostionToRemoveAt]; 

     Colours ColourToAssign = Colours[RandomColourPostion] ; 
     p.Color = ColourToAssign.ColourName; 
     Console.Write("Persons Name: " + p.Name +" Persons Colour:"+ p.Color); 
     Console.ReadLine(); 
    } 
}