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這是我的第一篇文章!如何從MySQL數據庫編輯記錄
首先,我有我的代碼,它在index.php上輸出一個表。最後我有一個編輯鏈接,帶我到edit.php頁:
if ($result->num_rows > 0) {
echo "<p><table><tr><th>ID</th><th>Film Name</th><th>Producer</th><th>Year Published</th><th>Stock</th><th>Price</th><th>Function</th></tr>";
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["ID"]."</td><td>".$row["FilmName"]."</td><td>".$row["Producer"]."</td><td>".$row['YearPublished']."</td><td>".$row['Stock']."</td><td>".$row['Price']."</td><td>"."<a href=\"edit.php\">Edit</a>/Delete"."</td></tr></p>";
}
echo "</table>";
edit.php(第一存在形式):
$query = "SELECT * FROM ProductManagement WHERE ID=" . $_GET["ID"] . ";"; // Place required query in a variable
$result = mysqli_query($connection, $query); // Execute query
if ($result == false) { // If query failed
echo "<p>Getting product details failed.</p>";
} else { // Query was successful
$productDetails = mysqli_fetch_array($result, MYSQLI_ASSOC); // Get results (only 1 row
// is required, and only 1 is returned due to using a primary key (id in this case) to
// get the results)
if (empty($productDetails)) { // If getting product details failed
echo "<p>No product details found.</p>"; // Display error message
}
}
?>
<form id="updateForm" name="updateForm" action="<?php echo "?mode=update&ID=" . $productDetails["ID"]; ?>" method="post">
<div>
<label for="updateFormProductCostPrice">ID</label>
<input id="updateFormProductCostPrice" name="ID" type="text" readonly
value="<?php echo $productDetails["ID"]; ?>">
</div>
<div>
<label for="updateFormProductName">Film Name</label>
<input id="updateFormProductName" name="FilmName" type="text" value="<?php echo $productDetails["FilmName"]; ?>">
</div>
<div>
<label for="updateFormProductDescription">Producer</label>
<textarea rows="4" cols="50" id="Producer"
name="productDescription"><?php echo $productDetails["Producer"]; ?></textarea>
</div>
<div>
<label for="updateFormProductPrice">Year Produced</label>
<input id="updateFormProductPrice" name="YearProduced" type="text"
value="<?php echo $productDetails["YearProduced"]; ?>">
</div>
<div>
<label for="updateFormProductStock">Stock:</label>
<input id="updateFormProductStock" name="Stock" type="text"
value="<?php echo $productDetails["Stock"]; ?>">
</div>
<div>
<label for="updateFormProductEan">Price:(£)</label>
<input id="updateFormProductEan" name="Price" type="text"
value="<?php echo $productDetails["Price"]; ?>">
</div>
<div>
<input id="updateSubmit" name="updateSubmit" value="Update product" type="submit">
</div>
</form>
</body>
再有就是PHP代碼更新記錄(編輯.php續):
if (((!empty($_GET["mode"])) && (!empty($_GET["id"]))) && ($_GET["mode"] == "update")) { // If update
echo "<h1>Update product</h1>";
if (isset($_POST["updateSubmit"])) { // If update form submitted
// Check all parts of the form have a value
if ((!empty($_POST["ID"])) && (!empty($_POST["FilmName"]))
&& (!empty($_POST["Producer"])) && (!empty($_POST["YearProduced"]))
&& (!empty($_POST["Stock"])) && (!empty($_POST["Price"]))) {
// Create and run update query to update product details
$query = "UPDATE products "
. "SET FilmName = '" . $_POST["FilmName"] . "', "
. "Producer = '" . $_POST["Producer"] . "', "
. "YearProduced = '" . $_POST["YearProduced"] . "', "
. "Stock = " . $_POST["Stock"] . ", "
. "Price = '" . $_POST["Price"] . "' "
. "WHERE id=" . $_GET['ID'] . ";";
$result = mysqli_query($connection, $query);
if ($result == false) { // If query failed - Updating product details failed (the update statement failed)
// Show error message
echo "<p>Updating failed.</p>";
} else{ // Updating product details was sucessful (the update statement worked)
// Show success message
echo "<p>Updated</p>";
}
}
}
}
我很抱歉,這裏有很多代碼。基本上,當我單擊主頁上的表中的編輯時,我希望它會加載所選行的數據,以便我可以更新它。
當前,當我點擊'編輯'鏈接時,它會加載編輯頁面,並且它有空白字段並且顯示「獲取產品詳細信息失敗」。如果它可以檢索所選相應行的數據,那將是非常好的。有人可以幫忙嗎?謝謝!
'ID'!='id' - 因此檢查PHP和SQL端的錯誤。你沒有那樣做。 –
請查閱以下鏈接http://php.net/manual/en/mysqli.error.php和http://php.net/manual/en/function.error-reporting.php 並將其應用於您的代碼。 –
還使用準備語句來避免SQL注入。 –