紅寶石字符串分割問題

我有這個字符串：「asdasda = asdaskdmasd & asmda = asdasmda & ACK =成功& asdmas = asdakmsd & asmda = adasda」紅寶石字符串分割問題

我想要的ACK之間後得到的值&象徵，ACK和&符號之間的值可以改變...

感謝

我想在紅寶石的解決方案。

2011-05-16 gal

require "cgi" 

query_string = "asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asmda=asdakmsd" 
parsed_query_string = CGI.parse(query_string) 
#=> { "asdasda" => ["asdaskdmasd"], 
#  "asmda" => ["asdasmda", "asdakmsd"], 
#  "ACK" => ["Success"] } 

parsed_query_string["ACK"].first 
#=> "Success"

如果你也想（用URL的其餘部分特別合）重建查詢字符串，我會建議尋找到了addressable寶石。

require "addressable/uri" 

# Note the leading '?' 
query_string = "?asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asmda=asdakmsd" 
parsed_uri = Addressable::URI.parse(query_string) 
parsed_uri.query_values["ACK"] 
#=> "Success" 

parsed_uri.query_values = parsed_uri.query_values.merge("ACK" => "Changed") 
parsed_uri.to_s 
#=> "?ACK=Changed&asdasda=asdaskdmasd&asmda=asdakmsd" 
# Note how the order has changed and the duplicate key has been removed due to 
# Addressable's built-in normalisation.

來源

2011-05-16 12:22:02 molf

+1用於獲取ACK沒有破解。 – 2011-05-16 22:55:53

s = "asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asdmas=asdakmsd&asmda=adasda" 
m = s.match /.*ACK=(.*?)&/ 
puts m[1]

，只是爲了好玩無正則表達式：

Hash[s.split("&").map{|p| p.split("=")}]["ACK"]

來源

2011-05-16 12:21:59

"asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asdmas=asdakmsd&asmda=adasda"[/ACK=([^&]*)&/] 
$1 # => 'Success'

來源

2011-05-16 12:23:39

一個快速的方法：

s = "asdasda=asdaskdmasd&asmda=asdasmda&ACK=Success&asdmas=asdakmsd&asmda=adasda" 
s.gsub(/ACK[=\w]+&/,"ACK[changedValue]&") 
    #=> asdasda=asdaskdmasd&asmda=asdasmda&ACK[changedValue]&asdmas=asdakmsd&asmda=adasda

來源

2011-05-16 12:25:32 intellidiot

紅寶石字符串分割問題

回答

相關問題