查詢返回基於性別的訪問者數量

Question

我有此查詢返回2個日期之間的訪問者數量。

$SQLVisit = "SELECT  
      count(score) as counts, 
      date FROM persons 
      WHERE date > '".$_SESSION['data1']."' AND date < '".$_SESSION['data2]."' 
      GROUP BY date 
      ORDER BY date asc"; 

$result = mysql_query($SQLVisit); 
$num = mysql_num_rows($result); 

這些訪問者，有些是男性和其他女性。

我已經有一個數組，使我的訪問次數和相應的日期。像這樣：['2012-1-1'，50]。 我的想法是有一個數組，可以保存日期，訪問次數，男性人數和女性人數。像這樣：['2012-1-1'，50,35.15]。

有什麼想法？ ps：使用PHP的Im。

編輯：數組代碼

$data[0] = array('day','counts');  
    for ($i=1; $i<($num+1); $i++) 
    { 
     $data[$i] = array(substr(mysql_result($result, $i-1, "date"), 0, 20), 
      (int) mysql_result($result, $i-1, "counts"),); 
    } 
    echo json_encode($data); 

EDIT2： 是的，我有一個性別（INT）柱，1男2女

Answer 1

如果你有gender列，儘量

$SQLVisit = "SELECT date, gender, 
        count(score) as counts, 
      FROM persons 
      WHERE date > '".$_SESSION['data1']."' AND date < '".$_SESSION['data2]."' 
      GROUP BY date, gender 
      ORDER BY date asc"; 

如果要格式化性別而不是數字，則要將其顯示爲male或female

$SQLVisit = "SELECT date, 
        IF(gender = 1, 'Male', 'Female') gender, 
        count(score) as counts, 
      FROM persons 
      WHERE date > '".$_SESSION['data1']."' AND date < '".$_SESSION['data2]."' 
      GROUP BY date, gender 
      ORDER BY date asc"; 

，如果你也也想擁有這樣的格式，

date Male  Female 
=========================== 
'date'  5   6 

使用以下查詢

SELECT DATE, 
     SUM(CASE WHEN gender = 1 then 1 ELSE 0 END) Male, 
     SUM(CASE WHEN gender = 2 then 1 ELSE 0 END) Female 
FROM person 
-- WHERE clause 
GROUP BY DATE 
-- ORDER clause 

查詢與SQL Injection脆弱的，請閱讀以下

文章

• How can I prevent SQL injection in PHP?

Answer 2

您可以使用SUM（IF（））：

$SQLVisit = "SELECT  
      count(score) as counts, 
      SUM(IF(gender=1,1,0)) as male, 
      SUM(IF(gender=2,1,0)) as female, 
      date FROM persons 
      WHERE date > '".$_SESSION['data1']."' AND date < '".$_SESSION['data2]."' 
      GROUP BY date 
      ORDER BY date asc"; 

Answer 3

你可以這樣做：

SELECT  
    SUM(CASE WHEN Gender = 1 THEN 1 ELSE 0) malescounts, 
    SUM(CASE WHEN Gender = 2 THEN 1 ELSE 0) femalescounts, 
    count(score) as counts 
FROM persons 
WHERE date > ... 
GROUP BY date;