如何將xml數據從一個sproc傳遞到另一個sproc？

Question

我有2 sprocs的任務，我想要做的是將xml輸出從一個sproc傳遞到另一個，並將其放入一個變量，我知道ex1.xml_sp1返回一個int，同時調用它與EXEC，顯然當試圖選擇它時它返回null，因爲@x是xml數據類型。

我想要做的是檢索和存儲過程從1 XML數據存儲在@x存儲過程2.

有沒有辦法做到這一點？

存儲過程1：

ALTER PROC [ex1].[xml_sp1] 
@careteamid int 
as 

select CareTeams.CareTeamID, Doctors.DoctorID, Doctors.DoctorName, 
    CareTeamDoctors.DateJoined, CareTeamDoctors.CurrentMember 
from dbo.CareTeamTbl as CareTeams 
inner join dbo.CareTeamDoctorTbl as CareTeamDoctors on 
CareTeams.CareTeamID = CareTeamDoctors.CareTeamID 
inner join dbo.DoctorTbl as Doctors on 
CareTeamDoctors.DoctorID=CareTeamDoctors.DoctorID 
where CareTeamDoctors.CareTeamID = @careteamid 
and CareTeamDoctors.DoctorID = Doctors.DoctorID 
for xml auto, root('thedata') 

存儲過程2：

ALTER PROC [ex1].[xml_sp2] 
@careteamid int 
as 
declare @x xml 

exec @x = ex1.xml_sp1 
      @careteamid = @careteamid 

select @x as XMLData 

Answer 1

我想要做的是檢索和存儲從存儲過程1中的XML數據在存儲過程@x 2

你可以實現它很容易使用OUTPUT parameters：

CREATE PROCEDURE [xml_sp1] 
    @careteamid INT, 
    @xml_output XML OUTPUT 
AS 
BEGIN 
    SET @xml_output = (SELECT * FROM ... FOR XML AUTO, root('thedata')); 
END; 
GO 

CREATE PROCEDURE [xml_sp2] 
    @careteamid INT 
AS 
BEGIN 
    DECLARE @x XML; 

    EXEC [xml_sp1] 
    @careteamid, 
    @x OUTPUT; 

    SELECT @x AS XMLData; 
END; 
GO 

和最終呼叫：

EXEC [xml_sp2] @careteamid = 1; 

LiveDemo

考慮使用BEGIN/END塊和結束每個語句;以避免可能討厭的問題。

可能的共享數據的方法How to Share Data between Stored Procedures by Erland Sommarskog

Answer 2

將這項工作？

declare @xml xml 
set @xml = (select * 
      from tableABC 
      for xml auto, elements) 

然後將該變量傳遞給另一個sproc？

我去的答案從這裏

How to insert FOR AUTO XML result into table?。

在我看來，這個想法是相似的，或應該工作類似。

Answer 3

爲什麼不嘗試，而不是分配SP1的輸出這將直接

declare @t table 
    (
    val xml 
    ) 

    insert into @t 
    exec ex1.xml_sp1 
    @careteamid = @careteamid 

    select * from @t 

Answer 4

對於返回值（即EXEC @ReturnValue = StoredProcName...;）的完整列表，INT是允許的唯一數據類型。如果這需要真正保留爲存儲過程，那麼您可以使用OUTPUT變量或在第二個存儲過程中創建臨時表或表變量，並執行INSERT INTO ... EXEC StoredProc1;。

然而，考慮到第一個存儲過程只是做一個簡單的SELECT語句，你會好得多轉換這是一個內聯表值函數（iTVF）如下：

CREATE FUNCTION dbo.GetData (@CareTeamID INT) 
RETURNS TABLE 
AS RETURN 

SELECT tab.col AS [CareData] 
FROM ( 
    SELECT CareTeams.CareTeamID, Doctors.DoctorID, Doctors.DoctorName, 
      CareTeamDoctors.DateJoined, CareTeamDoctors.CurrentMember 
    FROM dbo.CareTeamTbl as CareTeams 
    INNER JOIN dbo.CareTeamDoctorTbl as CareTeamDoctors 
      ON CareTeams.CareTeamID = CareTeamDoctors.CareTeamID 
    INNER JOIN dbo.DoctorTbl as Doctors 
      ON CareTeamDoctors.DoctorID=CareTeamDoctors.DoctorID 
    WHERE CareTeamDoctors.CareTeamID = @CareTeamID 
    AND CareTeamDoctors.DoctorID = Doctors.DoctorID 
    FOR XML AUTO, ROOT('thedata'), TYPE -- "TYPE" causes result to be XML and not NVARCHAR 
    ) tab(col); 

然後只是改變了第二個存儲過程是：

SELECT care.CareData AS [XMLData] 
FROM dbo.GetData(@CareTeamID); 

或者，如果你確實需要使用第二存儲過程XML數據，請執行以下操作：

DECLARE @TempData XML; 

SELECT @TempData = care.CareData 
FROM dbo.GetData(@CareTeamID); 

最後，如果您需要XML數據實際上是來自iTVF的XML數據類型（或者即使將它保存爲存儲過程），那麼您需要將TYPE選項添加到FOR XML子句中，還有什麼是返回是一個字符串/ NVARCHAR(MAX)：

FOR XML AUTO, ROOT ('thedata'), TYPE