SQL DB創建錯誤

我使用BIT DEFAULT 0,作爲布爾不知道它的權利是否如此。那麼，問題是我不能創建任何表，因爲在FK有問題，不明白爲什麼？我還添加了ERD圖像以獲得更好的視野。SQL DB創建錯誤

也許有人會/可以很好，並向我解釋，ty！

也許有人知道任何好的程序或在線沙箱的turtnind ERD的MSSQL代碼或MySQL代碼？如果免費使用它將會很好。提前致謝！

CREATE DataBase LO; 
GO 
USE LO; 

CREATE TABLE Weapon 
(
    ClassWeapon CHAR(50) NULL, 
    Level INT NULL, 
    MinDmg INT NULL, 
    MaxDmg INT NULL, 
    AtkSpeed NUMERIC(3,2) NULL, 
    PerSecondDmg NUMERIC(6,2) NULL, 
    PlayerLevel INT NULL, 
    SkillLevel INT NULL, 
    Image BIT DEFAULT 0 NULL, 
    Name CHAR(100) NULL, 
    Weapons CHAR(50) NOT NULL, 
    Monsters CHAR(50) NULL, 
    PRIMARY KEY (Weapons), 
    FOREIGN KEY (Monsters) REFERENCES Monster(Monsters) 
); 

CREATE TABLE Armor 
(
    ClassArmor CHAR(50) NULL, 
    Name CHAR(100) NULL, 
    Level INT NULL, 
    Defense INT NULL, 
    Image BIT DEFAULT 0 NULL, 
    Armors CHAR(50) NOT NULL, 
    Monsters CHAR(50) NULL, 
    PRIMARY KEY (Armors), 
    FOREIGN KEY (Monsters) REFERENCES Monster(Monsters) 
); 

CREATE TABLE Menu 
(
    Weapons CHAR(50) NULL, 
    Armors CHAR(50) NULL, 
    Monsters CHAR(50) NULL, 
    FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons), 
    FOREIGN KEY (Armors) REFERENCES Armor(Armors), 
    FOREIGN KEY (Monsters) REFERENCES Monster(Monsters) 
); 

CREATE TABLE Monster 
(
    Name CHAR(100) NULL, 
    Level INT NULL, 
    MinHealth INT NULL, 
    MaxHealth INT NULL, 
    MinDmg INT NULL, 
    MaxDmg INT NULL, 
    AtkSpeed NUMERIC(3,2) NULL, 
    Location CHAR(100) NULL, 
    Monsters CHAR(50) NOT NULL, 
    DropItems CHAR(100) NULL, 
    Image BIT DEFAULT 0 NULL, 
    PRIMARY KEY (Monsters), 
    FOREIGN KEY (DropItems) REFERENCES Items(DropItems) 
); 

CREATE TABLE Items 
(
    DropItems CHAR(100) NOT NULL, 
    Weapons CHAR(50) NULL, 
    Armors CHAR(50) NULL, 
    PRIMARY KEY (DropItems), 
    FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons), 
    FOREIGN KEY (Armors) REFERENCES Armor(Armors) 
);

來源

2017-08-01 eXme

1）創建表2）使用'ALTER TABLE'語法創建FK。在SQL中沒有前向聲明。例如武器會引用Monster表（不存在）。 – lad2025

好了，問題是，我不能創造任何表，因爲在FK一個問題，不知道爲什麼？

簡而言之，您不能引用不存在的對象。

，必須先創建表，然後添加FK關係：

CREATE DataBase LO; 
GO 
USE LO; 

CREATE TABLE Weapon 
(
    ClassWeapon CHAR(50) NULL, 
    Level INT NULL, 
    MinDmg INT NULL, 
    MaxDmg INT NULL, 
    AtkSpeed NUMERIC(3,2) NULL, 
    PerSecondDmg NUMERIC(6,2) NULL, 
    PlayerLevel INT NULL, 
    SkillLevel INT NULL, 
    Image BIT DEFAULT 0 NULL, 
    Name CHAR(100) NULL, 
    Weapons CHAR(50) NOT NULL, 
    Monsters CHAR(50) NULL, 
    PRIMARY KEY (Weapons), 
    --FOREIGN KEY (Monsters) REFERENCES Monster(Monsters) 
); 

CREATE TABLE Armor 
(
    ClassArmor CHAR(50) NULL, 
    Name CHAR(100) NULL, 
    Level INT NULL, 
    Defense INT NULL, 
    Image BIT DEFAULT 0 NULL, 
    Armors CHAR(50) NOT NULL, 
    Monsters CHAR(50) NULL, 
    PRIMARY KEY (Armors), 
---- FOREIGN KEY (Monsters) REFERENCES Monster(Monsters) 
); 

CREATE TABLE Menu 
(
    Weapons CHAR(50) NULL, 
    Armors CHAR(50) NULL, 
    Monsters CHAR(50) NULL, 
    --FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons), 
-- FOREIGN KEY (Armors) REFERENCES Armor(Armors), 
-- FOREIGN KEY (Monsters) REFERENCES Monster(Monsters) 
); 

CREATE TABLE Monster 
(
    Name CHAR(100) NULL, 
    Level INT NULL, 
    MinHealth INT NULL, 
    MaxHealth INT NULL, 
    MinDmg INT NULL, 
    MaxDmg INT NULL, 
    AtkSpeed NUMERIC(3,2) NULL, 
    Location CHAR(100) NULL, 
    Monsters CHAR(50) NOT NULL, 
    DropItems CHAR(100) NULL, 
    Image BIT DEFAULT 0 NULL, 
    PRIMARY KEY (Monsters), 
    --FOREIGN KEY (DropItems) REFERENCES Items(DropItems) 
); 

CREATE TABLE Items 
(
    DropItems CHAR(100) NOT NULL, 
    Weapons CHAR(50) NULL, 
    Armors CHAR(50) NULL, 
    PRIMARY KEY (DropItems), 
    --FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons), 
-- FOREIGN KEY (Armors) REFERENCES Armor(Armors) 
); 

ALTER TABLE Weapon 
ADD FOREIGN KEY (Monsters) REFERENCES Monster(Monsters); 

ALTER TABLE Armor 
ADD FOREIGN KEY (Monsters) REFERENCES Monster(Monsters); 

ALTER TABLE Menu 
ADD 
    FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons), 
    FOREIGN KEY (Armors) REFERENCES Armor(Armors), 
    FOREIGN KEY (Monsters) REFERENCES Monster(Monsters); 

ALTER TABLE Monster 
ADD FOREIGN KEY (DropItems) REFERENCES Items(DropItems); 

ALTER TABLE Items 
ADD FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons), 
FOREIGN KEY (Armors) REFERENCES Armor(Armors);

來源

2017-08-01 19:16:35 lad2025

謝謝同樣！ – eXme

或者更好的方法是更改正在創建的表的順序，以便在指定外鍵時存在這些表。 –

我覺得問題是在別的地方，我的ERD是一些錯誤，我猜...無論如何感謝.. – eXme

感謝@ lad2025

呢？這裏是如何工作的通過添加表，然後更改FK。

CREATE DataBase LO; 
GO 
USE LO; 

CREATE TABLE Weapon 
(
    ClassWeapon CHAR(50) NULL, 
    Level INT NULL, 
    MinDmg INT NULL, 
    MaxDmg INT NULL, 
    AtkSpeed NUMERIC(3,2) NULL, 
    PerSecondDmg NUMERIC(6,2) NULL, 
    PlayerLevel INT NULL, 
    SkillLevel INT NULL, 
    Image BIT DEFAULT 0 NULL, 
    Name CHAR(100) NULL, 
    Weapons CHAR(50) NOT NULL, 
    Monsters CHAR(50) NULL, 
    PRIMARY KEY (Weapons) 
); 
ALTER TABLE Weapon ADD FOREIGN KEY (Monsters) REFERENCES Monster(Monsters); 

CREATE TABLE Armor 
(
    ClassArmor CHAR(50) NULL, 
    Name CHAR(100) NULL, 
    Level INT NULL, 
    Defense INT NULL, 
    Image BIT DEFAULT 0 NULL, 
    Armors CHAR(50) NOT NULL, 
    Monsters CHAR(50) NULL, 
    PRIMARY KEY (Armors) 
); 
ALTER TABLE Armor ADD FOREIGN KEY (Monsters) REFERENCES Monster(Monsters); 

CREATE TABLE Menu 
(
    Weapons CHAR(50) NULL, 
    Armors CHAR(50) NULL, 
    Monsters CHAR(50) NULL 
); 
ALTER TABLE Menu ADD FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons); 
ALTER TABLE Menu ADD FOREIGN KEY (Armors) REFERENCES Armor(Armors); 
ALTER TABLE Menu ADD FOREIGN KEY (Monsters) REFERENCES Monster(Monsters); 

CREATE TABLE Monster 
(
    Name CHAR(100) NULL, 
    Level INT NULL, 
    MinHealth INT NULL, 
    MaxHealth INT NULL, 
    MinDmg INT NULL, 
    MaxDmg INT NULL, 
    AtkSpeed NUMERIC(3,2) NULL, 
    Location CHAR(100) NULL, 
    Monsters CHAR(50) NOT NULL, 
    DropItems CHAR(100) NULL, 
    Image BIT DEFAULT 0 NULL, 
    PRIMARY KEY (Monsters) 
); 
ALTER TABLE Monster ADD FOREIGN KEY (DropItems) REFERENCES Items(DropItems); 

CREATE TABLE Items 
(
    DropItems CHAR(100) NOT NULL, 
    Weapons CHAR(50) NULL, 
    Armors CHAR(50) NULL, 
    PRIMARY KEY (DropItems) 
); 
ALTER TABLE Items ADD FOREIGN KEY (Weapons) REFERENCES Weapon(Weapons); 
ALTER TABLE Items ADD FOREIGN KEY (Armors) REFERENCES Armor(Armors);

來源

2017-08-01 19:19:49 eXme

SQL DB創建錯誤

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