Python文件對話框問題

Question

我正在嘗試使用Tkinter來選擇一個文件，然後將該文件名導入一個參數以傳遞函數。該程序在文件被選擇後停止。我包含一個打印語句只是爲了查看它是否返回路徑，它確實如此，我不確定它爲什麼不能在函數中使用。

#Main 

from Tkinter import * 
import tkFileDialog 


fileOpen = Tk() 
fileOpen.withdraw() #hiding tkinter window 

file_path = tkFileDialog.askopenfilename(title="Open file", filetypes=[("txt file",".txt"),("All files",".*")]) 

if file_path != "": 
    print "you chose file with path:", file_path 

else: 
    print "you didn't open anything!" 

master.quit() 

print file_path 


spaceParser (file_path,'r','/Users/Desktop/TygerTygerParsed.txt','w') 

Answer 1

這（縮短的版本）工作得很好：

from Tkinter import * 
import tkFileDialog 

fileOpen = Tk() 
fileOpen.withdraw() #hiding tkinter window 

file_path = tkFileDialog.askopenfilename(
    title="Open file", filetypes=[("txt file",".txt"),("All files",".*")]) 

if file_path != "": 
    print "you chose file with path:", file_path 

else: 
    print "you didn't open anything!" 

print file_path 

所以我猜你的程序停止在

master.quit()