問題與顯示使用PHP

從MySQL的所有結果我使用該SQL查詢來從不同的表問題與顯示使用PHP

<? 
$sql = "SELECT gtem.gname AS itmnme, gvendor.gname AS vendor, gtem.col AS qty 
FROM gpopackageline 
LEFT JOIN gpo ON gpo.gpoid = gpopackageline.gpoid 
LEFT JOIN gtem ON gpopackageline.gtemid = gtem.gtemid 
LEFT JOIN gvendor ON gitem.gvendorid = gvendor.gvendorid 
WHERE gpopackageline.gpoid='".$sdo['swelid']."' "; 
$row = dblib_get_row_list($sql); 
?> 
<td class="contents51" width="100%"><?=$row['itmnme']?> </td> 
<td class="contents51" width="100%"><?=$row['vendor']?> </td> 
<td class="contents51" width="100%"><?=$row['qty']?> </td>

問題是我只得到1和第一結果印刷得到的結果。當我在phpMyAdmin測試查詢我得到的所有結果是否anyboby可以用這個幫忙，謝謝

來源

2014-01-09 sz_tech

你的'dblib_get_row_list'函數是怎麼樣的？ –

什麼是「dblib_get_row_list」？ – dwjv

也許你需要每個$行的循環？ –

你需要遍歷的結果，或者由while，或foreach - 這取決於你的邏輯。

例如

<? 
$sql = "SELECT gtem.gname AS itmnme, gvendor.gname AS vendor, gtem.col AS qty 
FROM gpopackageline 
LEFT JOIN gpo ON gpo.gpoid = gpopackageline.gpoid 
LEFT JOIN gtem ON gpopackageline.gtemid = gtem.gtemid 
LEFT JOIN gvendor ON gitem.gvendorid = gvendor.gvendorid 
WHERE gpopackageline.gpoid='".$sdo['swelid']."' "; 
$getRows = dblib_get_row_list($sql); //Assuming this returns everything in an assoc array 
foreach($getRows as $row) { 
?> 
<td class="contents51" width="100%"><?=$row['itmnme']?> </td> 
<td class="contents51" width="100%"><?=$row['vendor']?> </td> 
<td class="contents51" width="100%"><?=$row['qty']?> </td> 
<?php 
} 
?>

來源

2014-01-09 14:57:54

謝謝worksforeach –

沒有問題的所有:)很高興成爲幫助。 –

我不知道你是什麼dblib_get_row_list的回報。如果它返回數組，那麼它應該按照你的預期工作。

<? 
    $sql = "SELECT gtem.gname AS itmnme, gvendor.gname AS vendor, gtem.col AS qty 
    FROM gpopackageline 
    LEFT JOIN gpo ON gpo.gpoid = gpopackageline.gpoid 
    LEFT JOIN gtem ON gpopackageline.gtemid = gtem.gtemid 
    LEFT JOIN gvendor ON gitem.gvendorid = gvendor.gvendorid 
    WHERE gpopackageline.gpoid='".$sdo['swelid']."' "; 
    $result = dblib_get_row_list($sql); 
    foreach($result as $row){ 
    echo "<td class='contents51' width='100%'>".$row['itmnme']."</td>"; 
    echo "<td class='contents51' width='100%'>".$row['vendor']."</td>"; 
    echo "<td class='contents51' width='100%'>".$row['qty']."</td>"; 

    }

來源

2014-01-09 15:02:03

感謝作品「foreach」 –

問題與顯示使用PHP

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