PHP - 延長時鐘顯示23-24-25而不是23-00-01

Question

好的，所以這是我的第一個問題，所以請顯示一些憐憫。我正在開發一個Web應用程序來增加我在PHP編程方面的知識，但是我遇到了一個問題。

我的webapp是由時間驅動的。因此，例如當時鍾是17:00時，它顯示存儲在多維數組中的一條信息。而當時鍾是18:30時，它會顯示陣列中的其他信息。問題是，我有一些信息需要在例如25:12時顯示，而不改變當前日期。

所以問題： 你可以讓時鐘顯示時間爲24：00-25：00-26：00，而不是00：00-01：00-02：00，雖然仍是上同一天？比如說，時鐘在26:00之後，星期一將從星期一變爲星期二？這是一個多維數組的例子。它可以一直工作到23:59，但時鐘當然只會上升到00:00，當然也會改變。那麼你能在PHP中「延長」這一天嗎？

例子：

//This is one of the arrays I´ve got. This one only works on Monday-Friday. 
//It´s called "H103.php 
$tur = array 
(
array("RYEV", "6:26", "Møt", 1), 
array("RYEV", "6:36", "Uttak", 1), 
array("RYE2", "6:39+", "N", 1), 
array("FRS2", "7:29", "D", 1), 
array("FRS1", "7:43", "N", 1), 
array("BKR1", "8:47+", "N", 1), 
array("FRS2", "9:44", "D", 1), 
array("FRS1", "9:58", "N", 1), 
array("BKR1", "11:02+", "N", 1), 
array("FRS2", "11:59", "D", 1), 
array("FRS1", "12:13", "N", 1), 
array("BKR1", "13:17+", "N", 1), 
array("FRS1", "14:14", "D", 1), 
array("FRS1", "14:28", "N", 1), 
array("BKR1", "15:32+", "N", 1), 
array("FRS2", "16:29", "D", 1), 
array("FRS1", "16:43", "N", 1), 
array("BKR1", "17:47+", "N", 1), 
array("FRS2", "18:44", "D", 1), 
array("FRS1", "18:58", "N", 1), 
array("HFY2", "20:00+", "N", 1), 
array("FRS2", "20:44", "D", 1), 
array("FRS1", "20:58", "N", 1), 
array("HFY2", "22:00+", "N", 1), 
array("FRS2", "22:44", "D", 1), 
array("FRS1", "22:58", "N", 1), 
array("HFY2", "24:00+", "N", 1), 
array("FRS2", "24:47", "D", 1), 
array("MAJ3", "25:15", "D", 1), 
array("AVL2", "25:35", "D", 1), 
array("SPO6", "25:38", "Inn", 1), 
); 

//Define time into variable and counts array in total. 
$klokkeT = date("H:i"); 
$antT = count($tur); 
$u = 0; 

//Finding out which line from the array to take based on time, 
//and the storing it in a variable to show it on the website. 

if ($_SESSION["kjoreLinje"] == 1 && $_SESSION["retning"] == "O"){ 
for ($m = 0; $m < $antT; $m++) { 
    $u++; 
    if ($u < $antT) { 
     if ($klokkeT >= $tur[$m][1] AND $klokkeT <= $tur[$u][1]) { 
      $turF1 = $tur[$m][0]; $turF2 = $tur[$m][1]; $turF3 = $tur[$m][2]; 
      $turF4 = $tur[$m][3]; $turN1 = $tur[$u][0]; $turN2 = $tur[$u][1]; 
      $turN3 = $tur[$u][2]; $turN4 = $tur[$u][3]; 
     } } } 

//System choosing which file to take based on what day it is 
$weekdays = array("Monday", "Tuesday", "Wednesday", "Thursday", "Friday"); 

//weekdays 
for ($i = 0; $i < 5; $i++){ 
if ($_SESSION["day"] == $weekdays[$i]) { 
     if ($_SESSION["togNr"] == 103) { 
     include_once 'Kjoretavler/Hverdag/Linje1/H103.php'; } 
//Saturday 
if ($_SESSION["dag"] == "Saturday") { 
     if ($_SESSION["togNr"] == 103) { 
     include_once 'Kjoretavler/Lordag/Linje1/L103.php'; } 
//Sunday 
if ($_SESSION["dag"] == "Sunday") { 
     if ($_SESSION["togNr"] == 103) { 
     include_once 'Kjoretavler/Sondag/Linje1/S103.php'; } 

Answer 1

我@Andreas回答了一些修改工作。他似乎很清楚他已經取消了他的答案，所以我不能給他他應有的功勞。再次感謝，併爲錯誤的解釋感到抱歉。我已經學到了很多。編輯：代碼爲我工作。

if (date("G") <= 3) { 
    $day = Date("l", strtotime("yesterday")); 
    $time = 24 + intval(date("G")) . date(":i"); 
} else { 
    $day = date("l"); 
    $time = date("G:i"); 
} 
echo $day . " \n"; 
echo $time;