我在獲取Column時未發現錯誤,並且我無法弄清楚什麼是錯誤的,因此我尋求幫助。Hibernate持久性:列未找到
我需要生成一個列表Task
,其中引用User
和Project
。 我正在使用h2數據庫。
下面是表:
CREATE TABLE TASK.APP_USER (
id INT NOT NULL GENERATED ALWAYS AS IDENTITY,
username VARCHAR(25) NOT NULL,
firstName VARCHAR(25) NOT NULL,
lastName VARCHAR(25) NOT NULL,
password VARCHAR(32) NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE TASK.PROJECT (
id INT GENERATED ALWAYS AS IDENTITY,
name VARCHAR(50) NOT NULL,
companyName VARCHAR(50) NOT NULL,
PRIMARY KEY (id)
);
CREATE TABLE TASK.PROJECT_TASK (
id INT GENERATED ALWAYS AS IDENTITY,
projectId INT NOT NULL,
userId INT NOT NULL,
description VARCHAR(500) NOT NULL,
estimatedDurationHours INT NOT NULL,
PRIMARY KEY (id),
FOREIGN KEY (projectId) REFERENCES TASK.PROJECT(id),
FOREIGN KEY (userId) REFERENCES TASK.APP_USER(id),
);
下面是DAO類:
@Repository
public class TaskDaoHibernate implements TaskDao {
public TaskDaoHibernate() {
}
@Autowired
private SessionFactory sessionFactory;
private Session getCurrentSession() {
return sessionFactory.getCurrentSession();
}
@SuppressWarnings("unchecked")
@Override
public List<User> fetchAllUsers() {
return getCurrentSession().createQuery("from User").list();
}
@Override
public User fetchUserById(Integer userId) {
return (User) getCurrentSession().get(User.class, userId);
}
@SuppressWarnings("unchecked")
@Override
public List<Project> fetchAllProjects() {
return getCurrentSession().createQuery("from Project").list();
}
@Override
public Project fetchProjectById(Integer projectId) {
return (Project) getCurrentSession().get(Project.class, projectId);
}
@Override
public void saveTask(Task task) {
getCurrentSession().save(task);
}
@SuppressWarnings("unchecked")
@Override
public List<Task> fetchAllTasks() {
return getCurrentSession().createQuery("from Task").list();
}
@Override
public Task fetchTaskById(Integer taskId) {
return (Task) getCurrentSession().get(Task.class, taskId);
}
@Override
public void editTask(Task task) {
getCurrentSession().update(task);
}
public SessionFactory getSessionFactory() {
return sessionFactory;
}
public void setSessionFactory(SessionFactory sessionFactory) {
this.sessionFactory = sessionFactory;
}
}
這裏是同樣的原理User類,我已經規劃項目類:
@Entity
@Table(name="TASK.PROJECT")
public class Project implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1L;
@Id
@Column(name = "ID")
@GeneratedValue
private Integer id;
@Column(name = "NAME")
private String nazivProjekta;
@Column(name = "COMPANYNAME")
private String nazivTvrtke;
@ManyToOne
@JoinColumn(name="PROJECTID")
private Task task;
//setters, getters and overrided equal and hashcode methods
最後一類是Task類:
@Entity
@Table(name="TASK.PROJECT_TASK")
public class Task implements Serializable {
/**
*
*/
private static final long serialVersionUID = -4633753821563474175L;
@OneToMany(mappedBy="id", fetch=FetchType.EAGER)
private List<User> user;
@OneToMany(mappedBy="id", fetch=FetchType.EAGER)
private List<Project> project;
@Column(name = "DESCRIPTION ")
private String opisZadatka;
@Column(name = "ESTIMATEDDURATIONHOURS")
private Integer trajanje;
@Id
@Column(name = "ID")
@GeneratedValue
private Integer id;
public Task(){
}
這裏是堆棧跟蹤的beggining:
org.h2.jdbc.JdbcSQLException: Column "USER0_.USERID" not found; SQL statement:
select user0_.ID as ID1_2_0_, user0_.ID as ID1_0_0_, user0_.ID as ID1_0_1_, user0_.FIRSTNAME as FIRSTNAM2_0_1_, user0_.USERNAME as USERNAME3_0_1_, user0_.LASTNAME as LASTNAME4_0_1_, user0_.USERID as USERID5_0_1_, task1_.ID as ID1_2_2_, task1_.DESCRIPTION as DESCRIPT2_2_2_, task1_.ESTIMATEDDURATIONHOURS as ESTIMATE3_2_2_ from TASK.APP_USER user0_ left outer join TASK.PROJECT_TASK task1_ on user0_.USERID=task1_.ID where user0_.ID=? [42122-176]
at org.h2.message.DbException.getJdbcSQLException(DbException.java:344)
at org.h2.message.DbException.get(DbException.java:178)
at org.h2.message.DbException.get(DbException.java:154)
我認爲我已經發布的所有相關信息,但如果需要別的東西,我會很樂意將其添加
當您使用實體,每列將被映射到一個變量。你在'Task'類中有'List'用戶,但是你沒有列名:'userid',Hibernate不能引用它。 –
謝謝你的回答。我添加了annunci @Column(name =「USERID」)列,但我仍然遇到同樣的問題 – Sarpy