如何檢查按鈕是否存在或沒有在動作

Question

Im新的動作。如何檢查按鈕是否存在或不在動作。我想使用removechildname函數，嘗試它沒有成功。請幫助我。

Answer 1

也許這樣的事情會幫助你：

// Since you have a array with names, i think you can do this: 

// Get the length 
var lengthOfButtonsNamesArray:int = buttonsNamesArray.length; 
// looop through your array of names 
for(var index:int = 0; index < lengthOfButtonsNamesArray; ++index){ 
    // getting the button inside your buttons container using the array of names and getChildByName Method 
    var button:DisplayObject = buttonsContainer.getChildByName(buttonsNamesArray[index]) as DisplayObject; 
    // if the button was found 
    if(button != null){ 
     // remove it 
     buttonsContainer.removeChild(button); 
    } 
} 

/////////////////////// 
// OR 
////////////////////// 

// If you are sure that there are only buttons inside your buttons container and you want to remove all of them 

// Check the amount of children inside your buttons container 
// while its greater then zero, remove the child at index of zero 
while(buttonsContainer.numChildren > 0){ 
    buttonsContainer.removeChildAt(0); 
} 

我沒有測試，但我敢肯定，這個工作的，反正讓我知道你是如何做什麼。

Answer 2

使用contains()：

if (this.contains(myButton)) 
{ 
    // then we know myButton exists inside of this class 
    this.removeChild(myButton); // removeElement(), in some situations 
} 

if (myDisplayContainer.contains(myButton)) 
{ 
    // then we know myButton exists inside of myDisplayContainer 
    myDisplayContainer.removeChild(myButton); // removeElement(), in some 
               // situations 
}