刷新隨機在一個if case

Question

我生成兩個隨機的int數（a和b）。如果（a％b）== 0，我想繼續，否則我想通過刷新來更改隨機數。我舉個例子的代碼：

int a = //random; 
int b = //random; 
if ((a%b)==0) { 
    // do something 
} else { 
    // I want to change a and b and do that if case again. 
} 

Answer 1

int a= // random 
int b= // random 
while ((a%b)!=0) 
{ a = // random; 
    b = // random; 
} 
// a and b are random and out of the loop which means (a%b)==0 
// do something with a and b 

Answer 2

int a = //random; 
int b = //random; 
while((a%b)!=0) { 
    a = // random 
    b = // random 
} 
// do something 

所以在這種方式中，當A％B不等於0時，就會產生新的隨機a和b 當while循環的條件爲假它會停止產生這個，然後你可以恢復你的代碼