網絡速度調節

Question

我正在嘗試使用Python + pygtk + webkit構建瀏覽器。現在，我想節流的連接速度（即）加載一個網頁或下載速度的時間..主要是.. ..

所以，有沒有任何協議或webkit的方法，我可以使用相同的。以下是我的瀏覽器代碼。 Thankx提前！

import webkit 
import gobject 

class Browser: 
    default_site = "http://stackoverflow.com/" 

    def delete_event(self, widget, event, data=None): 
     return False 

    def destroy(self, widget, data=None): 
     gtk.main_quit() 

    def __init__(self): 
     gobject.threads_init() 
     self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) 
     self.window.set_resizable(True) 
     self.window.connect("delete_event", self.delete_event) 
     self.window.connect("destroy", self.destroy) 

     #webkit.WebView allows us to embed a webkit browser 
     #it takes care of going backwards/fowards/reloading 
     #it even handles flash 
     self.web_view = webkit.WebView() 
     self.web_view.open(self.default_site) 

     toolbar = gtk.Toolbar() 

     #create the back button and connect the action to 
     #allow us to go backwards using webkit 
     self.back_button = gtk.ToolButton(gtk.STOCK_GO_BACK) 
     self.back_button.connect("clicked", self.go_back) 

     #same idea for forward button 
     self.forward_button = gtk.ToolButton(gtk.STOCK_GO_FORWARD) 
     self.forward_button.connect("clicked", self.go_forward) 

     #again for refresh 
     refresh_button = gtk.ToolButton(gtk.STOCK_REFRESH) 
     refresh_button.connect("clicked", self.refresh) 

     #add the buttons to the toolbar 
     toolbar.add(self.back_button) 
     toolbar.add(self.forward_button) 
     toolbar.add(refresh_button) 

     #entry bar for typing in and display URLs, when they type in a site 
     #and hit enter the on_active function is called 
     self.url_bar = gtk.Entry() 
     self.url_bar.connect("activate", self.on_active) 

     #anytime a site is loaded the update_buttons will be called 
     self.web_view.connect("load_committed", self.update_buttons) 

     scroll_window = gtk.ScrolledWindow(None, None) 
     scroll_window.add(self.web_view) 


     vbox = gtk.VBox(False, 0) 
     vbox.pack_start(toolbar, False, True, 0) 
     vbox.pack_start(self.url_bar, False, True, 0) 
     vbox.add(scroll_window) 

     self.window.add(vbox) 
     self.window.show_all() 

    def on_active(self, widge, data=None): 
     '''When the user enters an address in the bar, we check to make 
      sure they added the http://, if not we add it for them. Once 
      the url is correct, we just ask webkit to open that site.''' 
     url = self.url_bar.get_text() 
     try: 
      url.index("://") 
     except: 
      url = "http://"+url 
     self.url_bar.set_text(url) 
     self.web_view.open(url) 

    def go_back(self, widget, data=None): 
     '''Webkit will remember the links and this will allow us to go 
      backwards.''' 
     self.web_view.go_back() 

    def go_forward(self, widget, data=None): 
     '''Webkit will remember the links and this will allow us to go 
      forwards.''' 
     self.web_view.go_forward() 

    def refresh(self, widget, data=None): 
     '''Simple makes webkit reload the current back.''' 
     self.web_view.reload() 

    def update_buttons(self, widget, data=None): 
     '''Gets the current url entry and puts that into the url bar. 
      It then checks to see if we can go back, if we can it makes the 
      back button clickable. Then it does the same for the foward 
      button.''' 
     #self.url_bar.set_text(widget.get_main_frame().get_uri()) 
     url = str(widget.get_main_frame().get_uri()) 
     print url 
     if (url == "http://www.facebook.com/"): 
      self.__go("age_error.html") 
     else:  
      self.url_bar.set_text(widget.get_main_frame().get_uri()) 
      print widget.get_main_frame().get_uri() 
      self.back_button.set_sensitive(self.web_view.can_go_back()) 
      self.forward_button.set_sensitive(self.web_view.can_go_forward()) 

    def main(self): 
     gtk.main() 

if __name__ == "__main__": 
    browser = Browser() 

    browser.main() 

Answer 1

如果有一種方法可以使用您自己的發送/接收代碼，您可以將它實現爲read（）+ sleep（）。例如，假設您希望它使用'50％帶寬'，那麼您需要花時間閱讀（），然後再睡一會兒。