MYSQL像，或者和，給出所有結果

這是我的代碼：

 SELECT a1.* 
     , t2.`name` AS project_name 
     , t2.`id` AS project_id 
     , u2.`fname` AS fname 
    , u2.`lname` AS lname 
    , u2.`color` AS color 
    , u2.`id` AS user_id 
    , u3.`fname` AS creatorfname 
    , u3.`lname` AS creatorlname 

    FROM `activities` AS a1 
    LEFT JOIN `projects` AS t2 ON a1.`projectid`=t2.`id` 
    LEFT JOIN `users` AS u2 ON a1.`userid`=u2.`id` 
    LEFT JOIN `users` AS u3 ON a1.`creatorid`=u3.`id` 
    LEFT JOIN `organisations` AS o1 ON u2.`orgid`=o1.`id` WHERE 
      o1.`id`=:orgid AND a1.`active`=1 OR a1.`postarea` LIKE '%newyork%' 
      OR a1.`streetname` LIKE '%newyork%' 
      OR a1.`companyname` LIKE '%newyork%' 
      OR a1.`postarea` LIKE '%newyork%' 
      OR a1.`orgnumber` LIKE '%newyork%' 
      OR a1.`postcode` LIKE '%newyork%' 
      OR a1.`homepage` LIKE '%newyork%' 
      OR a1.`phone1` LIKE '%newyork%' 
      OR a1.`phone2` LIKE '%newyork%' 
      OR a1.`phoneswitch` LIKE '%newyork%' 
      OR a1.`status` LIKE '%newyork%' 
      OR a1.`turnovermin` LIKE '%newyork%' 
      OR a1.`turnovermax` LIKE '%newyork%' 
      OR a1.`description` LIKE '%newyork%' 
      OR a1.`comment` LIKE '%newyork%' 
      OR a1.`email` LIKE '%newyork%' AND a1.`projectid`=:projectid  
      AND a1.`userid`=:userid AND a1.`date`>=:datefrom AND 
      a1.`date`<=:dateto ORDER BY a1.`date` DESC

的問題是，我得到一個基於或類似語句的每個結果。因此我使用PDO類，例如：orgid。它應該考慮所有的陳述和標準。我嘗試過（）和...等，但沒有任何結果。

希望得到一些幫助。

來源

2016-01-13 user1158040

'WHERE O1 \'ID \'=：。ORGID AND（OR值一束）和A 1 \'專案編號\'=：專案編號和A 1 \'的userid \'=：用戶標識和A1 \。 'date \'> =：datefrom AND a1 \'date \'<=：dateto' – MonkeyZeus

您需要了解邏輯括號。 – Utkanos

你必須告訴我們你想要的結果。你的陳述對我來說很奇怪，太複雜了。你爲什麼要問「紐約」10次？ – etalon11

使用()各地OR S，AND運營商具有較高的優先級因而OR之前應用。

SELECT a1.* 
    , t2.`name` AS project_name 
    , t2.`id` AS project_id 
    , u2.`fname` AS fname 
, u2.`lname` AS lname 
, u2.`color` AS color 
, u2.`id` AS user_id 
, u3.`fname` AS creatorfname 
, u3.`lname` AS creatorlname 

FROM `activities` AS a1 
LEFT JOIN `projects` AS t2 ON a1.`projectid`=t2.`id` 
LEFT JOIN `users` AS u2 ON a1.`userid`=u2.`id` 
LEFT JOIN `users` AS u3 ON a1.`creatorid`=u3.`id` 
LEFT JOIN `organisations` AS o1 ON u2.`orgid`=o1.`id` 
WHERE 
     o1.`id`=:orgid AND a1.`active`=1 AND 
     ( a1.`postarea` LIKE '%newyork%' 
     OR a1.`streetname` LIKE '%newyork%' 
     OR a1.`companyname` LIKE '%newyork%' 
     OR a1.`postarea` LIKE '%newyork%' 
     OR a1.`orgnumber` LIKE '%newyork%' 
     OR a1.`postcode` LIKE '%newyork%' 
     OR a1.`homepage` LIKE '%newyork%' 
     OR a1.`phone1` LIKE '%newyork%' 
     OR a1.`phone2` LIKE '%newyork%' 
     OR a1.`phoneswitch` LIKE '%newyork%' 
     OR a1.`status` LIKE '%newyork%' 
     OR a1.`turnovermin` LIKE '%newyork%' 
     OR a1.`turnovermax` LIKE '%newyork%' 
     OR a1.`description` LIKE '%newyork%' 
     OR a1.`comment` LIKE '%newyork%' 
     OR a1.`email` LIKE '%newyork%' 
     ) 
     AND a1.`projectid`=:projectid  
     AND a1.`userid`=:userid AND a1.`date`>=:datefrom AND 
     a1.`date`<=:dateto ORDER BY a1.`date` DESC

來源

2016-01-13 19:08:37 Vasfed

非常感謝你！你真的救了我的夜晚：D那個人完美無缺。我會用圓括號來看看這些東西。 – user1158040

您需要了解邏輯括號。

a AND b OR c OR d意味着邏輯污染。括號告訴處理器能夠執行哪些操作了第一，而不是排名每個相等：

a AND (b OR c) - 如果A是真實的和B或C也真

(a AND b) OR c - 如果A和B都爲真，或不管他們的，如果C是真實的，而不是

來源

2016-01-13 19:08:35 Utkanos

說的很好@Utkanos！ –

MYSQL像，或者和，給出所有結果

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