的WebSocket送交

Question

我目前正在做的PHP

$room_array = array(); 
$room_array[0] = 'room-list'; 
$room_array['info'] = array('room_name' => $room['room_name'], 'owner' => $username['username'], 'room_description' => $room['room_desc']); 
socket_send($this->current_socket, $this->encode(json_encode($room_array)), strlen($this->encode(json_encode($room_array))), 0); 

以下內容，這是我的編碼功能

private function encode($text) 
    { 
     $b1 = 0x80 | (0x1 & 0x0f); 
     $length = strlen($text); 

     if($length <= 125) 
      $header = pack('CC', $b1, $length); 
     elseif($length > 125 && $length < 65536) 
      $header = pack('CCS', $b1, 126, $length); 
     elseif($length >= 65536) 
      $header = pack('CCN', $b1, 127, $length); 

     return $header.$text; 
    } 

而且我的客戶在我處理像這樣

message = JSON.parse(event.data); 
     console.log(message) 
     switch(message[0]) 
     { 
      case 'error': 
       alert(message[1]); 
       break; 
      case 'login-success': 
       $('#user_information').html('<button class="user-name-button">Welcome <b>' + message.name + '</b></button><button class="user-coins-button"><b>' + message.coins + '</b> Coins</button>'); 
       socket.send(JSON.stringify({'room_list': message.name})); 
       break; 
      case 'room-list': 
       alert(1) 
       break; 
     } 

因此，使用此代碼alert（1）正在執行，但問題是如果我嘗試以下（添加更多元素到數組中）套接字不會工作。該消息將被髮送，但不會到達客戶端。不知道爲什麼

$room_array = array(); 
    $room_array[0] = 'room-list'; 
    $room_array['test'] = 'hello'; 
    $room_array['info'] = array('room_name' => $room['room_name'], 'owner' => $username['username'], 'room_description' => $room['room_desc']); 
    socket_send($this->current_socket, $this->encode(json_encode($room_array)), strlen($this->encode(json_encode($room_array))), 0); 

Answer 1

使用單例對象。

$http->execute($room_array); 
$room_array->parse_request(this->returnFive()); 
$http->send_request(); 

public returnFive(){ 
    return 5; 
}