在bash中使用sed替換heredoc字符串

Question

在bash腳本中，我需要用一些heredoc替換文件中的佔位符字符串。我怎麼做？

例如sed -i 's/PLACEHOLDER_TEXT/$HEREDOC/g' > file.txt其中

<<HEREDOC 
Some multiple 
lines of 
text to replace PLACEHOLDER_TEXT 
HEREDOC 

Answer 1

通trhough一個臨時文件，並避免的替代品，由於更換圖案特殊字符的行爲可能發生（如&，\x）

所以

cat > /tmp/HereFile <<HEREDOC 
Some multiple 
lines of 
text to replace PLACEHOLDER_TEXT 
HEREDOC 

sed '/PLACEHOLDER_TEXT/ { 
    r /tmp/HereFile 
    d 
    }' YourFile 
rm /tmp/HereFile 

Answer 2

只需壓平（你可以改變＃如果可能會出現在你的數據），並把新行早在以後類似：

sed "s/PLACEHOLDER_TEXT/$(echo "$HEREDOC"|tr "\n" "#")/g;s/#/\n/g" file.txt 

要構建$ HEREDOC變量：

$> export HEREDOC=$(cat<<EOF 

    > what is going 
    > on with 
    > this 
    > thing 
    > EOF 
    >) 

Answer 3

試試這個命令：

val=$(tr '\n' ' ' < PlaceHolderText.txt); sed "s/PLACEHOLDER/$val/" File.txt 

實施例：

sdlcb@Goofy-Gen:~/AMD$ cat PlaceHolderText.txt 
Some multiple 
lines of 
text to replace 

sdlcb@Goofy-Gen:~/AMD$ cat File.txt 
This is a text with PLACEHOLDER for some additional data. 

sdlcb@Goofy-Gen:~/AMD$ val=$(tr '\n' ' ' < PlaceHolderText.txt); echo $val; sed "s/PLACEHOLDER/$val/" File.txt 
This is a text with Some multiple lines of text to replace for some additional data.