錯誤：SQLITE_ERROR：接近「0」：語法錯誤

Question

我只想創建一列並向其中添加一些值，但出現兩個錯誤。一個是如果我取消註釋db.close（）;手柄關閉太快，另一個是Error: SQLITE_ERROR: near "0": syntax error下面是代碼。

var file = "DB.sqlite3"; 
var sqlite3 = require("sqlite3").verbose(); 
var db = new sqlite3.Database(file); 

if(!fs.existsSync(file)) fs.openSync(file, "w"); 

db.serialize(function() {   
    db.run(`CREATE TABLE IF NOT EXISTS players (id INTEGER)`); 
    for(var i = 0; i < 10; i++) 
    { 
     db.run(`SELECT EXISTS(SELECT 1 FROM players WHERE id=${i})`, function(error, row) { 
      if (row === undefined) 
       db.run(`INSERT INTO players (id) VALUES (?)`,i); 
      if(error) console.log(error); 
     }); 
    } 
}); 
//db.close(); //if I uncomment I get that the handle has closed 

Answer 1

我不知道，因爲我只是一個初學者，但我覺得你dbclose需要去最後的支架像這裏面：

var file = "DB.sqlite3"; 
var sqlite3 = require("sqlite3").verbose(); 
var db = new sqlite3.Database(file); 

if(!fs.existsSync(file)) fs.openSync(file, "w"); 

db.serialize(function() {   
    db.run(`CREATE TABLE IF NOT EXISTS players (id INTEGER)`); 
    for(var i = 0; i < 10; i++) 
    { 
     db.run(`SELECT EXISTS(SELECT 1 FROM players WHERE id=${i})`, function(error, row) { 
      if (row === undefined) 
       db.run(`INSERT INTO players (id) VALUES (?)`,i); 
      if(error) console.log(error); 
     }); 
    } 
db.close(); 
});