跨越多個HttpURLConnection請求維護登錄令牌

Question

對不起，問你這個問題，但我有點新Java。

我有以下類別：

protected class LoginMethod{ 
     public LoginMethod() throws MalformedURLException, UnsupportedEncodingException, IOException{ 
     URL url = new URL("http://example.com/login"); 
     Map<String,Object> params = new LinkedHashMap<>(); 
     params.put("username", user); 
     params.put("password", password); 

     StringBuilder postData = new StringBuilder(); 
     for (Map.Entry<String,Object> param : params.entrySet()) { 
      if (postData.length() != 0) postData.append('&'); 
      postData.append(URLEncoder.encode(param.getKey(), "UTF-8")); 
      postData.append('='); 
      postData.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8")); 
     } 
     byte[] postDataBytes = postData.toString().getBytes("UTF-8"); 
     try{ 
      HttpURLConnection conn = (HttpURLConnection)url.openConnection(); 
      conn.setRequestMethod("POST"); 
      conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); 
      conn.setRequestProperty("Content-Length", String.valueOf(postDataBytes.length)); 
      conn.setDoOutput(true); 
      conn.getOutputStream().write(postDataBytes); 

      Reader in = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8")); 
      for (int c = in.read(); c != -1; c = in.read()) 
       token += String.valueOf((char)c); 
      System.out.println(token); 
      new LoggedIn(); 
     }catch(IOException es){ 
      System.out.println(es); 
     } 
     } 

    } 

這將返回一個JSON字符串的一些標記。 而接下來類：

protected class DoStuff{ 
     public DoStuff() throws MalformedURLException, UnsupportedEncodingException, IOException, ParseException{ 
      JSONParser parser = new JSONParser(); 
      URL url = new URL("http://example.com/DoStuff"); 
      Map<String,Object> params = new LinkedHashMap<>(); 

      params.put("Do", "Stuff"); 
      StringBuilder postData = new StringBuilder(); 
      for (Map.Entry<String,Object> param : params.entrySet()) { 
       if (postData.length() != 0) postData.append('&'); 
       postData.append(URLEncoder.encode(param.getKey(), "UTF-8")); 
       postData.append('='); 
       postData.append(URLEncoder.encode(String.valueOf(param.getValue()), "UTF-8")); 
      } 
      byte[] postDataBytes = postData.toString().getBytes("UTF-8"); 
       try{ 
       HttpURLConnection conn = (HttpURLConnection)url.openConnection(); 
       conn.setRequestMethod("POST"); 
       conn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded"); 
       conn.setRequestProperty("Content-Length", String.valueOf(postDataBytes.length)); 
       conn.setDoOutput(true); 
       conn.getOutputStream().write(postDataBytes); 

       Reader in = new BufferedReader(new InputStreamReader(conn.getInputStream(), "UTF-8")); 
       for (int c = in.read(); c != -1; c = in.read()) 
        stuff +=(char)c; 
       System.out.println(stuff); 
       new LogOut(); 
       }catch(IOException er){ 
        System.out.println(er); 
       } 

     } 

    } 

這將返回DoStuff事情。但是因爲我不知道如何保持這些類之間的會話，所以我得到了401錯誤。 我的問題是如何保持這些類之間的會話或提示如何將它們放入支持會話的單個類中，記住它們由單獨的按鈕調用。 謝謝！

Answer 1

正確的答案是： 在我們需要JSON解碼接收的令牌，並添加第二類

conn.setRequestProperty("Authorization", token); 

This works。感謝StackOverflow的一切。

Answer 2

如果提到的「http://example.com」是一個web服務，您在響應中收到的令牌具有會話信息。所有你需要做的就是在調用dostuff方法時通過設置請求頭來發回令牌。

登錄響應：

{ "token":"ewryoiuasdjhie8417098412","expires":"jun 10 2015"} 

同時呼籲dostuff

conn.setRequestProperty("token", "ewryoiuasdjhie8417098412");