在android中顯示圖像使用位圖的延遲

Question

我從設備接收到連續的UDP數據（RAW圖像）。解碼和使用位圖顯示

我的Android手機，所以它會看起來像一個視頻。問題是，幀不連續顯示

。框架變化約。每2〜3秒但我想在1/30中逐幀顯示。

下面是我的代碼

public class ArDroneMain extends Activity { 
    Bitmap image = null; 
    public ImageView myImageView; 
    protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    animationDrawable = new AnimationDrawable(); 
    myImageView = (ImageView)findViewById(R.id.imageView); 
    thread.start(); 
    } 
} 

Thread thread=new Thread (new Runnable() { 
     Message message; 
    String obj="run";  
    @Override 
    public void run() { 

    while(true){  
     try { 
      Log.e("enter_video_thread","enter_video_thread"); 
      receiveVideoRawData(); 
      Log.e("///receiveVideoRawData ","receiveVideoRawData"); 
      message = handler.obtainMessage(1,obj); 
        handler.sendMessage(message); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } 
    } 
    } 
    public Handler handler = new Handler(){ 


    @SuppressLint("NewApi") 
    @Override 
    public void handleMessage(Message msg) { 
      super.handleMessage(msg);   
      String MsgString = (String)msg.obj; 
      if (MsgString.equals("run")) 
      {                     
          Drawable ardrone_Frame_Drawable =newBitmapDrawable(getResources(),image); 
         animationDrawable.addFrame(ardrone_Frame_Drawable,100); 
         myImageView.setBackground(animationDrawable);      



      } 


    } 
}; 


    public void sendTriggerCommand() throws IOException{ 
     byte [] ip_bytes = new byte[] {(byte)192,(byte)168,(byte)1,(byte)1};//Drone address 
     byte[] buf_snd = {0x01, 0x00, 0x00, 0x00};//trigger buffer 
     inet_addr = InetAddress.getByAddress(ip_bytes); 
     DatagramPacket packet_snd = new DatagramPacket(buf_snd, buf_snd.length, i net_addr, ardrone_video_port);  
     socket_video.send(packet_snd); 

} 

    public void receiveVideoRawData() throws IOException{ 
    Log.e("enter_receiveVideoRawData()","enter_receiveVideoRawData()"); 
    socket_video = new DatagramSocket(); 
    byte[] buf_rcv = new byte[153600]; 
    DatagramPacket rawData = new DatagramPacket(buf_rcv, buf_rcv.length); 
     sendTriggerCommand(); 
     Log.e("sendTriggerCommand();","sendTriggerCommand();"); 
     socket_video.receive(rawData); 
     Log.e("socket_video.receive(rawData);","socket_video.receive(rawData);"); 
     ReadRawFileImage readMyRawData=new ReadRawFileImage(); 

     image = readMyRawData.readUINT_RGBImage(buf_rcv); 

}

Answer 1

部分我真的懷疑你能以最快的速度接收數據，尤其是原始圖像。

，你可以做些什麼來改善你的程序可能是：

• 發送和接收壓縮數據
• 刪除，而真正的循環，它永遠不會動手。你應該使用布爾標誌來控制你的線程。
• 使用的AsyncTask來接收數據，它在解碼背景，然後在UI線程顯示它
• 使用2線程與線程同步：一個從網絡讀取數據時，消耗該數據，並將其顯示的第二個。這將是一個更好的架構，流水線2個任務。