由於源表和目標表的文件組不匹配而導致交換分區失敗

Question

我想在其中一個表上實現交換機分區，並且確保分區函數，方案，文件組正常工作。但是當我運行下面的命令時，我得到文件組錯誤。有人可以分享你的想法。

命令： -

ALTER TABLE XYZ SWITCH PARTITION 5 TO ABC PARTITION 5; 

錯誤： -

ALTER TABLE switch語句失敗。表'XYZ'在文件組'PRIMARY'中，表'ABC'的分區5在文件組'FG_5'中。

Answer 1

某些集羣索引可能會在現有表上創建。因此，在可能不同的表上創建羣集索引期間會提到文件組。或者如果你可以刪除ABC表並重新創建並嘗試你的查詢。

查詢檢查表和索引名稱的文件組。

select f.name,o.name,i.name from sys.indexes i inner join sys.filegroups f on i.data_space_id=f.data_space_id 
inner join sys.all_objects o on o.object_id= i.object_id 
where o.name in ('ABC','XYZ') 

我不會說這是解決方案，但這應該有助於解決問題。

Answer 2

該錯誤指示源表和目標表不存儲對齊。運行下面的查詢以確保源文件組和目標文件組在表和索引中都相同：

SELECT 
    OBJECT_NAME(p.object_id) AS ObjectName, 
    i.name AS IndexName, 
    p.index_id AS IndexID, 
    ds.name AS PartitionScheme, 
    p.partition_number AS PartitionNumber, 
    fg.name AS FileGroupName, 
    prv_left.value AS LowerBoundaryValue, 
    prv_right.value AS UpperBoundaryValue, 
    CASE pf.boundary_value_on_right WHEN 1 THEN 'RIGHT' ELSE 'LEFT' END AS PartitionFunctionRange, 
    p.rows AS Rows 
FROM 
    sys.partitions AS p INNER JOIN 
    sys.indexes AS i ON i.object_id = p.object_id AND i.index_id = p.index_id INNER JOIN 
    sys.data_spaces AS ds ON ds.data_space_id = i.data_space_id INNER JOIN 
    sys.partition_schemes AS ps ON ps.data_space_id = ds.data_space_id INNER JOIN 
    sys.partition_functions AS pf ON pf.function_id = ps.function_id INNER JOIN 
    sys.destination_data_spaces AS dds2 ON dds2.partition_scheme_id = ps.data_space_id AND dds2.destination_id = p.partition_number INNER JOIN 
    sys.filegroups AS fg ON fg.data_space_id = dds2.data_space_id LEFT OUTER JOIN 
    sys.partition_range_values AS prv_left ON ps.function_id = prv_left.function_id AND prv_left.boundary_id = p.partition_number - 1 LEFT OUTER JOIN 
    sys.partition_range_values AS prv_right ON ps.function_id = prv_right.function_id AND prv_right.boundary_id = p.partition_number 
WHERE 
    p.object_id IN (
     OBJECT_ID(N'dbo.ABC') 
     , OBJECT_ID(N'dbo.XYZ') 
    ) 
    AND p.partition_number = 5 
ORDER BY 
    ObjectName 
    ,IndexName 
    ,PartitionNumber;