有一個簡單的技巧可以將連續的條目合併到一個組中。如果按(row_number - entry)進行分組,則連續的條目將在同一組中結束。這裏有一個例子展示了我的意思:
查詢:
SELECT phonenum, @curRow := @curRow + 1 AS row_number, phonenum - @curRow
from phonenums p
join (SELECT @curRow := 0) r
結果:
| PHONENUM | ROW_NUMBER | PHONENUM - @CURROW |
-------------------------------------------------
| 27100070000 | 1 | 27100069999 |
| 27100070001 | 2 | 27100069999 |
| 27100070002 | 3 | 27100069999 |
| 27100070003 | 4 | 27100069999 |
| 27100070004 | 5 | 27100069999 |
| 27100070005 | 6 | 27100069999 |
| 27100070008 | 7 | 27100070001 |
| 27100070009 | 8 | 27100070001 |
| 27100070012 | 9 | 27100070003 |
| 27100070015 | 10 | 27100070005 |
| 27100070016 | 11 | 27100070005 |
| 27100070040 | 12 | 27100070028 |
注意,是連續的所有條目如何有PHONENUM - @CURROW
相同的值。如果我們組上欄,並選擇分鐘&最大每一組的,你有總結(有一個例外:你可以用NULL
更換終值,如果start =結束時,如果這是一個要求):
查詢:
select min(phonenum), max(phonenum) from
(
SELECT phonenum, @curRow := @curRow + 1 AS row_number
from phonenums p
join (SELECT @curRow := 0) r
) p
group by phonenum - row_number
結果:
| MIN(PHONENUM) | MAX(PHONENUM) |
---------------------------------
| 27100070000 | 27100070005 |
| 27100070008 | 27100070009 |
| 27100070012 | 27100070012 |
| 27100070015 | 27100070016 |
| 27100070040 | 27100070040 |
演示:http://www.sqlfiddle.com/#!2/59b04/5
我不知道SQL,但PHP(或真正的任何堂兄弟)是微不足道的。 –