這是我在追蹤呼叫顯示錯誤代碼片段:爲什麼我得到TypeError:需要一個整數?
def categorize(title):
with conn:
cur= conn.cursor()
title_str= str(title)
title_words= re.split('; |, |\*|\n',title_str)
key_list= list(dictionary.keys())
flag2= 1
for word in title_words:
title_letters= list(word)
flag1= 1
for key in key_list:
if key==title_letters[0]:
flag1= 0
break
if flag1== 0:
start=dictionary.get(title_letters[0])
end= next_val(title_letters[0])
for i in xrange (start,end):
if word==transfer_bag_of_words[i]:
flag2= 0
break
if flag2== 0:
cur.execute("select Id from articles where title=title")
row_id= cur.fetchone()
value= (row_id,'1')
s= str(value)
f.write(s)
f.write("\n")
break
return
def next_val(text):
for i,v in enumerate(keyList):
if text=='t':
return len(transfer_bag_of_words)
elif v==text:
return dictionary[keyList[i+1]]
這是回溯電話:
Traceback (most recent call last):
File "categorize_words.py", line 93, in <module>
query_database()
File "categorize_words.py", line 45, in query_database
categorize(row)
File "categorize_words.py", line 67, in categorize
for i in xrange (start,end):
TypeError: an integer is required
我沒有這裏給出的整個代碼。但我會解釋我正在嘗試做什麼。我試圖從sqlite數據庫中導入一個特定的字段,並檢查字段中的單個字是否與我的程序中已有的特定字符相匹配。我已經對這些單詞進行了簡單的分類,並且使用python字典爲它的索引分配了每一個新字母的開頭。我已經這樣做了,每當我檢查字詞袋中的字時,我就不必循環整個單詞。相反,我可以從這個詞的第一個字母的索引開始循環。
我檢查過,字典中get()的返回類型是int,函數nextVal也應該返回一個int,因爲len()和dictionary [keylist [i + 1]]都是int類型。
請幫忙。
編輯
這是我的全部代碼:
import sqlite3 as sql
import re
conn= sql.connect('football_corpus/corpus2.db')
transfer_bag_of_words=['transfer','Transfer','transfers','Transfers','deal','signs','contract','rejects','bid','rumours','swap','moves',
'negotiation','negotiations','fee','subject','signings','agreement','personal','terms','pens','agent','in','for',
'joins','sell','buy','confirms','confirm','confirmed','signing','renew','joined','hunt','excited','move','sign',
'loan','loaned','loans','switch','complete','offer','offered','interest','price','tag','miss','signed','sniffing',
'remain','plug','pull','race','targeting','targets','target','eye','sale','clause','rejected',
'interested']
dictionary={}
dictionary['a']=0;
keyList=[]
f= open('/home/surya/Twitter/corpus-builder/transfer.txt','w')
def map_letter_to_pos():
pos=0
transfer_bag_of_words.sort()
for word in transfer_bag_of_words:
flag=1
letters= list(word)
key_list= list(dictionary.keys())
for key in key_list:
if key==letters[0]:
flag=0
break
if flag==1:
dictionary[letters[0]]=pos
pos+=1
else:
pos+=1
keyList= sorted(dictionary.keys())
def query_database():
with conn:
cur= conn.cursor()
cur.execute("select title from articles")
row_titles= cur.fetchall()
for row in row_titles:
categorize(row)
def categorize(title):
with conn:
cur= conn.cursor()
title_str= str(title)
title_words= re.split('; |, |\*|\n',title_str)
key_list= list(dictionary.keys())
flag2= 1
for word in title_words:
title_letters= list(word)
flag1= 1
for key in key_list:
if key==title_letters[0]:
flag1= 0
break
if flag1== 0:
start=dictionary.get(title_letters[0])
end= next_val(title_letters[0])
for i in xrange (start,end):
if word==transfer_bag_of_words[i]:
flag2= 0
break
if flag2== 0:
cur.execute("select Id from articles where title=title")
row_id= cur.fetchone()
value= (row_id,'1')
s= str(value)
f.write(s)
f.write("\n")
break
return
def next_val(text):
for i,v in enumerate(keyList):
if text=='t':
return len(transfer_bag_of_words)
elif v==text:
return dictionary[keyList[i+1]]
if __name__=='__main__':
map_letter_to_pos()
query_database()
這是下載鏈接到數據庫文件http://wikisend.com/download/702374/corpus2.db
這需要[mcve]。如果這兩個變量的類型確實是int,那麼這不成問題。 –
@ joelgoldstick我不明白。我已經提供了給出錯誤 –
'start'和/或'end'的代碼部分不是整數。我知道你說過你檢查了他們,但你錯了。 –